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nikitadnepr [17]
3 years ago
8

When a 1.50V battery is shorted by a copper wire whose resistance can be ignored, the current through the copper wire is 2.75 A.

What is the internal resistance of the battery?
Physics
1 answer:
viva [34]3 years ago
5 0

Answer:

Internal resistance = 0.545 ohm

Explanation:

As per ohm's law we know that

V = iR

here we know that

i = electric current = 2.75 A

V = potential difference = 1.50 Volts

now from above equation we have

1.50 = 2.75 ( R)

now we have

R = \frac{1.50}{2.75}

R = 0.545 ohm

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Si se aplica una fuerza de 3n sobre un sistema se genera 15000 cal de calor generandose a su vez un trabajo de 300 j ¿en cuanto
Marizza181 [45]

Answer: +/- 71,65 Calorías

Explanation: Se deduce que la fuerza aplica para aumentar o disminuir la energía del generador.

+/- x Calorías

X = Equivalente de 300 Joules en calorías

Para poder pasar Joules a calorías.

Hacemos una regla de 3 simple

1 Calorías = 4,18 Julios

0,2392 calorías = 1 Julio

(  1 / 4,18 = 0,2392 calorías)

300 Julios = 71,65 calorías

(0,2392 calorías x 300 julios = +/- 71,65 calorías)

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3 years ago
Why does a balloon filled with hydrogen rises up only to a certain height​
KengaRu [80]

Answer: they will rise up because hydrogen is lighter in density and it's weight is lower when it's in the air

Explanation:

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4 years ago
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What is the path of object due to gravitational forces
fiasKO [112]

if drppoed then locally path vertical down ... towards centre of earth

7 0
3 years ago
A boat with a mass of 1000 kg drifts with the current down a straight section of river parallel to the +x+x axis with a speed of
IrinaK [193]

Answer:

A.

Explanation:

Our values are defined by,

m=1000kg\\v = 2m/s\\a = 2.7 \angle 45\°

We can express also in a vectorial way, then

v=2\hat{i} \rightarrowno values in \hat{j}

Acceleration as follow,

a= 2.7cos45 \hat{i} + 2.7 sin45 \hat{j}

We know that velocity is given by,

V(t) = v_0+at \rightarrow v_0 = 2

We need to calculate for t=3, then

v(3) = 2\hat{i} +(2.7cos45 \hat{i} + 2.7 sin45 \hat{j})*3

v(3) = (2\hat{i}+3*2.7cos45 \hat{i})+(3*2.7 sin45 \hat{j})

v(3) = (2+3*2.7cos45)\hat{i}+(5.7 sin45 )\hat{j}

v(3) = 7.7\hat{i}+5.7\hat{j}

Our mass is 1000Kg, so the momentum is

P = mv

P= 1000(7.7\hat{i}+5.7\hat{j})

P=7700\hat{i}+5700\hat{j}

7 0
4 years ago
A plane is flying due west at 34 m/s. It encounters a wind blowing at 19 m/s south. Find the resultant veloci
Drupady [299]

Answer:

<em>The resultant velocity has a magnitude of 38.95 m/s</em>

Explanation:

<u>Vector Addition</u>

Given two vectors defined as:

\vec v_1=(x_1,y_1)

\vec v_2=(x_2,y_2)

The sum of the vectors is:

\vec v=(x_1+x_2,y_1+y_2)

The magnitude of a vector can be calculated by

d=\sqrt{x^2+y^2}

Where x and y are the rectangular components of the vector.

We have a plane flying due west at 34 m/s. Its velocity vector is:

\vec v_1=(-34,0)

The wind blows at 19 m/s south, thus:

\vec v_2=(0,-19)

The sum of both velocities gives the resultant velocity:

\vec v =(-34,-19)

The magnitude of this velocity is:

d=\sqrt{(-34)^2+(-19)^2}

d=\sqrt{1156+361}=\sqrt{1517}

d = 38.95 m/s

The resultant velocity has a magnitude of 38.95 m/s

3 0
3 years ago
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