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4 years ago

Help asap please im confused

Physics

1 answer:

solmaris [256]4 years ago

5 0

Answer:

Motivation

Explanation:

motivation can be a limiting factor that can involve a person's feelings regarding his or her weight

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Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller

jekas [21]

Answer:

$F_2 = 29.54 N$

Explanation:

As we know that the combination is maintained at rest position

So we will take net torque on the system to be ZERO

so we know that

$\tau = \vec r \times \vec F$

here we will have

$\vec r_1 \times F_1 = \vec r_2 \times F_2$

so we have

$13 \times 50 = 22 \times F_2$

so we have

$F_2 = \frac{13 \times 50}{22}$

$F_2 = 29.54 N$

8 0

4 years ago

3. Identify three elements and three compounds. How are they<br> similar? How are they different?

Basile [38]

Answer: A compound is a substance formed when two or more elements are chemically joined. Water, salt, and sugar are examples of compounds. When the elements are joined, the atoms lose their individual properties and have different properties from the elements they are composed of.

6 0

3 years ago

A helicopter blade spins at exactly 100 revolutions per minute. Its tip is 5.00 m from the center of rotation. (a) Calculate the

Illusion [34]

angular vel to tangential vel

v=r omega

v = 56 x 100/60 x 2 pi

v = 56x5/3x6

v=560m/s as estimate

100 revs, 5.00m

5 0

3 years ago

Read 2 more answers

A passenger train travels 392 mi in the same time that it takes a freight train to travel 322 mi. If the passenger train travels

Yuri [45]

Answer:

Explanation:

Given

distance traveled by Passenger train is $d_1=392\ mi$

distance traveled by Freight train is $d_2=322\ mi$

Both take same time to travel

suppose speed of freight train is x mph

so speed of passenger train is 20+x mph

we know time $=\frac{distance}{speed}$

$t=\frac{392}{20+x}=\frac{322}{x}$

$392x=322x+322\times 20$

$70x=322\times 20$

$x=92\ mph$

speed of passenger train $x+20=112\ mph$

6 0

3 years ago

A fluid flows along the x axis with a velocity given by V = ( x / t ) ˆ i , where x is in feet and t in seconds. (a) Plot the sp

umka21 [38]

Answer:

V_local = -x/t^2

V_convec = x/t^2

a = V_local + V_convec = 0

e) When a particle moves towards postive x direction its convective velocity increases, but at the same time the local velocity deacreases (at the same rate) when time increases

Explanation:

Hi!

You can see plots for a) and b) attached on this document

The local acceleration is just teh aprtial derivative of the velocity with respect to t:

$\frac{dV}{dt} = \frac{d}{dt} \frac{x}{t}=- \frac{x}{t^2}$

And the convective acceleration is given by the product of the velocity times the gradient of the velocity, that is:

$\vec{v} \cdot \nabla \vec{v} = v ( \frac{dv}{dx} ) =\frac{x}{t} \frac{1}{t} = \frac{x}{t^2}$

Since the acceleration of any fluid particle is the sum of the local and convective accelerations, we can easily see that it is equal to zero, since they are equal but with opposit sign

This is because of teh particular form of the velocity. A particle will move towards areas of higher velocities (convectice acceleration), but as time increases, the velocity is also decreasing (local acceleration), and the sum of these quantities adds up to zero

3 0

4 years ago