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4 years ago

Help asap please im confused

Physics

1 answer:

solmaris [256]4 years ago

5 0

Answer:

Motivation

Explanation:

motivation can be a limiting factor that can involve a person's feelings regarding his or her weight

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A 36.5-g glass thermometer reads 23.6 âˆ˜C before it is placed in 145 mL of water. When the water and thermometer come to equili

adoni [48]

The initial temperature of the water was $41.6688^{0} C$ .

Given,

Weight of glass 36.5g

specific heat for glass is 840 J/kgâ‹…Câˆ˜.

Initial temperature of glass was $23.6^{0} C$ .

Weight of water is 145*1=145g (Density*Volume=145ml*1g/ml)

Temperature final was $40.8^{0} C$ .

specific heat for water is 4186 J/kgâ‹…Câˆ

(m of glass)(Cp of glass)(Tf_glass-Ti_glass) = (m of water)(Cp of water)(Ti_water - Tf_water)

36.5*840*(40.8-23.6)=145*4186*(Ti_water - 40.8)

Ti_water= $41.6688^{0} C$

<h3>Specific heat</h3>

In thermodynamics, a material's specific heat capacity, or massic heat capacity as it is sometimes known, is equal to the heat capacity of a sample of the substance divided by the mass of the sample (symbol cp). Informally, it is the quantity of heat needed to raise a substance's temperature by one degree for every unit of mass that is added to it. joule per kelvin per kilogram, or Jkg1K1, is the SI unit for specific heat capacity. For instance, the amount of energy needed to increase the temperature of 1 kilogram of water by 1 K is 4184 joules, making water's specific heat capacity 4184 J kg 1 K 1.

Learn more about specific heat here:

brainly.com/question/11297584

#SPJ4

8 0

2 years ago

Light of wavelength 656 nm and 410 nm emitted from a hot gas of hydrogen atoms strikes a grating with 5300 lines per centimeter.

padilas [110]

Answer:

$20.32^{\circ}$ and $44.08^{\circ}$

$12.56^{\circ}$ and $25.77^{\circ}$

Explanation:

$\lambda$ = Wavelength

$\theta$ = Angle

m = Order

Distance between grating is given by

$d=\dfrac{1}{5300}\\\Rightarrow d=0.0001886\ \text{cm}$

$\lambda=656\ \text{nm}$

We have the relation

$d\sin\theta=m\lambda\\\Rightarrow \theta=\sin^{-1}\dfrac{m\lambda}{d}$

m = 1

$\theta=\sin^{-1}\dfrac{1\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=20.35^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=44.08^{\circ}$

The first and second order angular deflection is $20.32^{\circ}$ and $44.08^{\circ}$

$\lambda=410\ \text{nm}$

m = 1

$\theta=\sin^{-1}\dfrac{1\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=12.56^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=25.77^{\circ}$

The first and second order angular deflection is $12.56^{\circ}$ and $25.77^{\circ}$ .

4 0

3 years ago

A car leaves an intersection traveling west. Its position 4 sec later is 21 ft from the intersection. At the same time, another

Alex_Xolod [135]

Answer:

15.8 ft/s

Explanation:

$\frac{da}{dt}$ = Velocity of car A = 9 ft/s

a = Distance car A travels = 21 ft

$\frac{db}{dt}$ = Velocity of car B = 13 ft/s

b = Distance car B travels = ft

c = Distance between A and B after 4 seconds = √(a²+b²) = √(21²+28²) = √1225 ft

From Pythagoras theorem

a²+b² = c²

Now, differentiating with respect to time

$2a\frac{da}{dt}+2b\frac{db}{dt}=2c\frac{dc}{dt}\\\Rightarrow a\frac{da}{dt}+b\frac{db}{dt}=c\frac{dc}{dt}\\\Rightarrow \frac{dc}{dt}=\frac{a\frac{da}{dt}+b\frac{db}{dt}}{c}\\\Rightarrow \frac{dc}{dt}=\frac{21\times 9+28\times 13}{\sqrt{1225}}\\\Rightarrow \frac{dc}{dt}=15.8\ ft/s$

∴ Rate at which distance between the cars is increasing three hours later is 15.8 ft/s

6 0

4 years ago

What has to happen for a feather and ball to fall at the same time

Alex_Xolod [135]

This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height. ... When air resistance plays a role, the shape of the object becomes important. In air, a feather and a ball do not fall at the same rate.

4 0

4 years ago

A cylindrical shell of radius 7.00 cm and length 2.21 m has its charge uniformly distributed on its curved surface. The magnitud

polet [3.4K]

Answer:

The net charge on the shell is 30x10^-9C

Explanation:

Pls see attached file

8 0

4 years ago