Answer:
5 cm³.
Explanation:
The following data were obtained from the question:
Volume of water = 35 mL
Volume of water + Rock = 40 mL
Volume of rock =.?
The volume of the rock can be obtained as follow:
Volume of rock = (Volume of water + Rock) – (Volume of water)
Volume of rock = 40 – 35
Volume of rock = 5 mL
Finally, we shall convert 5 mL to cm³. This can be obtained as illustrated below:
1 mL = 1 cm³
Therefore,
5 mL = 5 cm³
Thus, the volume of the rock is 5 cm³.
Answer:
8 oxygen. 9 flourine. 10. Neon. 5 Boron
Answer:
We have 8.4 * 10^10 nickel atoms
Explanation:
step 1: Data given
Mass of nickel = 8.30 * 10^-12 grams
Number of avogadro = 6.02 * 10^22 / mol
Atomic mass nickel = 58.69 g/mol
Step 2: Calculate moles nickel
Moles nickel = mass nickel / atomic mass nickel
Moles nickel = 8.30 * 10^-12 grams / 58.69 g/mol
Moles nickel = 1.4*10^-13 moles
Step 3: Calculate nickel atoms
Nickel atoms = moles nickel * number of Avogadro
Nickel atoms = 1.4 * 10^-13 moles * 6.02 * 10^23 /mol
Nickel atoms = 8.4* 10^10 atoms
We have 8.4 * 10^10 nickel atoms
10 mL of 0.1 M NaOH is equal to 1 equivalent of base, if titrating 10.00 mL of 0.1 M amino acid.
Given :
0.1 M NaOH
0.1 M Amino acid
10.00 mL volume of Amino acid
<em> R-CH(NH₂)-COOH + NaOH → R-CHNH₂Na + H₂O</em>
In this case, end factor = 1 and It is 1 mole / 1 mole ratio
Since, the concentration of amino acid and NaOH are same, that is 0.1 M.
Concentration of amino acid = concentration of NaOH
0.1 M = 0.1 M
Therefore, 10 mL of NaOH is required to neutralize 10 mL of amino acid and the end factor is equivalent to 1.
Hence, The volume of 0.1 M NaOH is equal to 1 equivalent of base.
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Answer:
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