Answer:
Explanation:
Analogy:
Who does more work:
Work done is defined as the product of force and distance. Work is done when force moves a body in a particular direction.
In this case, work done is the same thing as the potential energy of the weight.
Work done = potential energy = m x g x h
Mass of weight = 100kg for both Mike and Brian
g is the acceleration due to gravity
h is the height
Since they lifted the weight through the same height;
Work done by Mike = 100gh
Work done by Brian = 100gh
Both Mike and Brian does equal work
Who generates more power:
Power is the rate at which work is done;
Power =
Power generated by Mike = = 50gh
Power generated by Brian = = 33.33gh
We can see that Mike generated more power
The flux of is given by the surface integral
where is the given square region, which we can parameterize by
with and
. The area element is
where is the normal vector to
. Depending on the orientation of
, this vector could be
or ; either way, the integral reduces to
Answer: 52 kg skydiver: 9.09 m/s and 522.55 s
95 kg skydiver: 12.3 m/s and 386.2 s
Explanation: <u>Drag</u> <u>Force</u> is an opposite force when an object is moving in a fluid.
For skydivers, when falling through the air, the forces acting on it are gravitational and drag forces. At a certain point, drag force equals gravitational force, which is constant on any part of the planet, producing a net force that is zero. Since there is no net force, there is no acceleration and, consequently, velocity is constant. When that happens, the person reached the <u>Terminal</u> <u>Velocity</u>.
Drag Force and Velocity are proportional to the squared speed. So, terminal velocity is given by:
where
m is mass in kg
g is acceleration due to gravitational force in m/s²
ρ is density of the fluid in kg/m³
C is drag coefficient
A is area of the object in the fluid in m²
Calculating:
The 52kg skydiver has terminal velocity of:
9.09
The 95kg skydiver's terminal velocity is
12.3
The 52 kg and 95kg skydivers' terminal velocity are 9.09m/s and 12.3m/s, respectively.
The time each one will reach the floor will be:
52 kg at 9.09 m/s:
t = 522.5
95 kg at 12.3 m/s:
t = 386.2
The 52 kg and 95kg skydivers' time to reach the floor are 522.5 s and 386.2 s, respectively.