Question

How to Answer questions 12 and 13

Answer 1

12) The weight of the plane is $7.35\cdot 10^5 N$

13) The lift provided by the wing is $7.35\cdot 10^5 N$

Explanation:

12)

The weight of an object is equal to the force of gravity acting on the object. Near the Earth's surface, it can be calculated as

$W=mg$

where

W is the weight

m is the mass of the object

g is the acceleration of gravity

In this problem, we know that the mass of the plane is

m = 75 tonnes

Since 1 ton = 1000 kg, the mass in kg is

m = 75,000 kg

Also, the acceleration of gravity is

$g=9.8 m/s^2$

Therefore, the weight of the plane is:

$W=(75,000)(9.8)=7.35\cdot 10^5 N$

13)

We can solve this question by applying Newton's second law along the vertical direction of motion. In fact, the net force acting along the vertical direction must be equal to the product between the mass of the plane and the vertical acceleration:

$\sum F_y = ma_y$

where

$\sum F_y$ is the net force in the y-direction

m is the mass of the plane

$a_y$ is the acceleration in the y-direction

There are two forces acting in the vertical direction:

• The lift L, acting upward
• The weight W, acting  downward

So the vertical net force is

$\sum F_y = L-W$

And the equation becomes

$L-W = ma_y$

Also, we know that the plane is travelling in level flight, which means that the vertical acceleration is zero:

$a_y = 0$

Therefore, we get

$L-W=0$

And so the lift is

$L=W=7.35\cdot 10^5 N$

Learn more about  forces:

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