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topjm [15]
3 years ago
13

Which of these elements is a noble gas? hydrogen (H) barium (Ba) nitrogen (N) krypton (Kr) bromine (Br)

Chemistry
2 answers:
ruslelena [56]3 years ago
8 0
Krypton...it is based off of its location on the periodic table
NNADVOKAT [17]3 years ago
3 0

Answer : The correct option is krypton (Kr).

Explanation :

Noble gas : It is a group which is present at last in the periodic table and they belongs to group 18.

The general electronic configuration of noble gas is (ns^2np^6).

The noble gas contains six elements which are helium, neon, argon, krypton, xenon and radon.

According to the question,

  • Hydrogen belongs to group 1 which is a alkali metal.

The general electronic configuration of hydrogen is (ns^1).

  • Barium belongs to group 2 which is an alkaline earth metal.

The general electronic configuration of barium is (ns^2).

  • Nitrogen belongs to group 15 which is a non-metal.

The general electronic configuration of nitrogen is (ns^2np^3).

  • Bromine belongs to group 17 which is a halogen.

The general electronic configuration of bromine is (ns^2np^5).

  • Krypton belongs to group 18 which is a noble gas.

The general electronic configuration of krypton is (ns^2np^6).

Therefore, the correct answer is krypton (Kr).

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Answer:

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Explanation:

Let us first take a look at the image below;

In the acid - base  reaction; we can see the transfer of electrons that takes place;

We can also see that the reaction goes in the direction which converts the stronger acid and the stronger base to the weaker acid and the weaker base.

The stronger acid is shown with the one with more negative P_{Ka} Value.

∴ The equilibrium constant for the acid-base reaction is expressed as:

K_{eq}= \frac{K_a of reactant acid}{K_a of product acid}

      = \frac{10^{-pK} of reactant acid}{10^{-pk} of product acid}

From  P_{Ka} Value (shown in the image below), it is clear and vivid that hydrobromic acid is a stronger acid than the ethyloxonium ion, therefore the equilibrium lies to the right.

From the chemical equation (shown in the attached image); the equilibrium constant for the acid-base reaction can be expressed as:

K_{eq}=\frac{10^{-pK} of hydrobromic acid}{10^{-pk} of Ethyloxonium acid}

K_{eq}=\frac{10^{-5.8} of hydrobromic acid}{10^{-2.4} of Ethyloxonium acid}

       = 10^{-3.4}

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