Answer:
q = 4.04×10^-12C
n = 2.53×10^7
Explanation:
1. Electrostatic force on charge due to electrical field E is F = qE
Gravitational force due to weight of drop of mass M is F = mg, when net force is zero we have to find the charges on the drop.
2. Charge on drop: since gravitational force is acting downward, electric field is acting upward and we equate both equations.
Therefore, Fg = Fe
qe = mg
q = mg/E
q = 3.50×10^-9kg×9.8m/s²/8480N/c
q = 4.04 × 10^-12
3. Number of protons by quantitization law
n = q/e
n = 4.04× 10^-12/8480
n = 2.53× 10^7
We will use the formula p = mgh
p is potential energy.
m is mass of object in kg
g is acceleration due to gravity (9.8m/s²)
h is height of the objects displacement in meters.
p = mgh → mgh = p → h = p / mg
p is 14000j, m is 40kg and g is 9.8 m/s²
h = 14000 / 40 × 9.8 → h = 1400 / 392 → h = 35.7
Therefore , the cannonball was 35.7 meters high .
Answer:
A flat, horizontal line
Explanation:
A flat, horizontal line indicates a phase change.
The temperature does not increase because the added heat goes into converting one phase into another.
A is wrong. A downward-sloping line indicates that the temperature is decreasing with time.
C is wrong. An upward-sloping line indicates that the temperature is increasing with time.
C. Nuclear power does not produce any form of pollution.
Answer:3,2,4,5,1
Explanation:
I just did it on edgenuity
