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3 years ago

11

Based on the assumption that a liquid conducting core and rapid rotation are both required for a magnetic field to operate, whic

h terrestrial planets would you expect to have magnetic fields?

1 answer:

Verizon [17]3 years ago

3 0

answer is earth. Earth is having everything that is required for a magnetic field to operate.

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A Newtonian fluid with a viscosity  drains through the space between two large parallel plates as shown in the figure. The gap

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A coastal forest was home to a type of burrowing rodent that was not found anywhere else in the world. A year ago, a species of

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You are 12 miles north of your base camp when you begin walking north at a speed of 2mph. what is your location, relative to you

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3 years ago

Which is a component of pseudoscience, but not science?

quester [9]

Answer:

The statements, observations, beliefs and suppositions all are the components of the pseudoscience.

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The claims included in the pseudoscience including the beliefs, statements and practices are claimed to be scientific but these are devoid of any scientific evidences provided by the experimental procedures.

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3 years ago

A(n) 55.5 g ball is dropped from a height of 53.6 cm above a spring of negligible mass. The ball compresses the spring to a maxi

Serggg [28]

Answer:

The spring force constant is $k=243\ \frac{N}{m}$ .

Explanation:

We are told the mass of the ball is $m=0.0555\ kg$ , the height above the spring where the ball is dropped is $h=0.536\ m$ , the length the ball compresses the spring is $d=0.04897\ m$ and the acceleration of gravity is $9.8\ \frac{m}{s^{2}}$ .

We will consider the initial moment to be when the ball is dropped and the final moment to be when the ball stops, compressing the spring. We supose that there is no friction so the initial mechanical energy $E_{mi}$ is equal to the final mechanical energy $E_{mf}$ :

$E_{mf}=E_{mi}$

Initially there is only gravitational potential energy because the force of the spring isn't present and the speed is zero. In the final moment there is only elastic potential energy because the height is zero and the ball has stopped. So we have that:

$\frac{1}{2}kd^{2}=mgh$

If we manipulate the equation we have that:

$k=\frac{2mgh}{d^{2} }$

$k=\frac{2\ 0.0555\ kg\ 9.8\frac{m}{s^{2}}\ 0.536\ m}{(0.04897)^{2}m^{2}}$

$k=\frac{0.58306\ \frac{kgm^{2}}{s^{2}}}{2.398x10^{-3}m^{2}}$

$k=243\ \frac{N}{m}$

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3 years ago