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lisov135 [29]
3 years ago
11

Based on the assumption that a liquid conducting core and rapid rotation are both required for a magnetic field to operate, whic

h terrestrial planets would you expect to have magnetic fields?
Physics
1 answer:
Verizon [17]3 years ago
3 0

answer is earth. Earth is having everything that is required for a magnetic field to operate.

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The body is subjected to a force of 0,4 N m with a shoulder of 5 cm. What is the magnitude of this force?​
igor_vitrenko [27]

Answer:

8N

Explanation:

the body is subjected to pressure equals to force force inverse to the area of that body given that it is in motion

5 0
2 years ago
A roller coaster car moving at a velocity of 30 meters/second has a momentum of 2.5 × 104 kilogram meters/second. what is its ma
frez [133]

The mass of a rollercoaster car moving at a velocity of 30 meters/second and has a momentum of 2.5 × 104 kilogram meters/second is 8.3 × 10²kg.

<h3>How to calculate mass?</h3>

The mass of the roller coaster car can be calculated using the following formula:

P = m × v

Where;

  • P = momentum
  • m = mass
  • v = velocity

m = 2.5 × 10⁴ ÷ 30

m = 8.3 × 10²kg

Therefore, the mass of a rollercoaster car moving at a velocity of 30 meters/second and has a momentum of 2.5 × 104 kilogram meters/second is 8.3 × 10²kg.

Learn more about mass at: brainly.com/question/19694949

#SPJ1

8 0
2 years ago
A 16.2 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The
S_A_V [24]

To solve this problem we will apply the concepts related to the balance of forces. We will decompose the forces in the vertical and horizontal sense, and at the same time, we will perform summation of torques to eliminate some variables and obtain a system of equations that allow us to obtain the angle.

The forces in the vertical direction would be,

\sum F_x = 0

f-N_w = 0

N_w = f

The forces in the horizontal direction would be,

\sum F_y = 0

N_f -W =0

N_f = W

The sum of Torques at equilibrium,

\sum \tau = 0

Wdcos\theta - N_wLsin\theta = 0

WdCos\theta = fLSin\theta

f = \frac{Wd}{Ltan\theta}

The maximum friction force would be equivalent to the coefficient of friction by the person, but at the same time to the expression previously found, therefore

f_{max} = \mu W=\frac{Wd}{Ltan\theta}

\theta = tan^{-1} (\frac{d}{\mu L})

Replacing,

\theta = tan^{-1} (\frac{0.9}{0.42*2})

\theta = 46.975\°

Therefore the minimum angle that the person can reach is 46.9°

8 0
3 years ago
The__ of friction is a number that represents the resistance to sliding
Tresset [83]

Answer:

B. coefficient

Explanation:

i dont have to explain right?

3 0
3 years ago
If a lamp has a resistance of 50 ohms and is operated by a p.d. of 10V, find the current flowing through it
NemiM [27]
V=IR therefore I=V/R=10/50=0.2A therefore the current is 0.2 A
4 0
3 years ago
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