Question

A flat, rectangular coil consisting of 60 turns measures 23.0 cm by 31.0 cm . It is in a uniform, 1.20-T, magnetic field, with the plane of the coil parallel to the field. In 0.210 s , it is rotated so that the plane of the coil is perpendicular to the field.Part A What is the change in the magnetic flux through the coil due to this rotation?Part B Find the magnitude of the average emf induced in the coil during this rotation.

Answer 1

Answer:25.23 V

Explanation:

Given

no of turns $N=60 turns$

Magnetic Field $B=1.2 T$

Area of rectangular coil $A=23\times 31=713 cm^2\approx 0.0713m^2$

Change in magnetic Flux is given by

$\Delta \phi =BA\cos \theta$

$\Delta \phi =1.2\times 0.0736\cos 0=0.08832 V-s$

(b)Emf induced change in Flux with respect to time and it can be given by

$E=-N\frac{\mathrm{d} \phi }{\mathrm{d} t}$

$E=-60\times \frac{0.08832}{0.21}$

$E=-25.23 V$

The magnitude of emf induced is $25.23 V$