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ladessa [460]
3 years ago
12

A scientist in a lab would like to determine if an object conducts electricity. Which of the following experiments would test th

is? A. Place the object on a source of heat, and measure the time it take to heat up. B. Float the object in water. C. Include the object in a circuit, and check to see if the circuit still works. D. Weight the object before and after refrigeration. ​
Physics
2 answers:
lubasha [3.4K]3 years ago
7 0

Answer: C. Include the object in a circuit

Explanation:

mr Goodwill [35]3 years ago
6 0

A scientist in a lab would like to determine if an object conducts electricity. How could he test this ?

A. <u>Place the object on a source of heat</u>, and measure the time it take to heat up.  <em>No.  This would  tell him how well the object conducts heat, but not electricity. </em>

B. <u>Float the object in water.</u>  <em>No.  This would tell him the object's density, and also maybe how well it can absorb water, but nothing about conducting electricity. </em>

<em>C. Include the object in a circuit,</em> and check to see if the circuit still works.  <em>YES !</em><em>  If the circuit still works, then the object conducts electricity.  If it doesn't then it doesn't. </em>

D. <u>Weight the object</u> before and after refrigeration.  <em>No.  This doesn't tell him much of anything ... there's no reason why the object should weigh more or weigh less when it's warm or cold.​</em>

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Technician A says that current is created in the stator windings of an alternator. Technician B says that the voltage regulator
drek231 [11]

Answer:

Technician A and Technician B both are right.

Explanation:

In an AC alternator,  there are two windings

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Therefore, both technicians are right.

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The note created by a flute will increase the speed of sound increases. When a marching band goes outside on a cold day, what wo
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A manufacturer claims its cleanser works twice as fast as any other. Could test be performed to support the claim? Explain
lora16 [44]

Yes, a test could be performed to support the claim.

 

Hypothesis: The claim that a manufacturer’s cleanser works twice as fast as any other cleanser.

 

So, based from this hypothesis, we can perform the following tests:

We assign Cleanser A to the manufacturer that claims that their cleanser works twice as fast as any other cleanser and Cleanser B to the cleanser to be compared with.

 

1.       Get two tiles and put the same amount of stain on them.

2.       Apply Cleanser A on the first tile and Cleanser B on the second tile.

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The resistivity of a metal increases slightly with increased temperature. This can be expressed as rho= rho0[1+α(T−T0)] , where
Stolb23 [73]

Answer:

At 81. 52 Deg C its resistance will be 0.31 Ω.

Explanation:

The resistance of wire =R_T =\frac{\rho_T \ l}{A}

Where R_T =Resistance of wire at Temperature T

\rho_T = Resistivity at temperature T =\rho_0 \ [1 \ + \alpha\ (T-T_0\ )]

Where T_0 =20\ Deg\ C , \  \rho_0 = Constant,  \alpha =3.9 \times 10^-^3 DegC^-1 \ (Given)

l=Length of the wire

& A = Area of cross section of wire

For long and thin wire the resistance & resistivity relation will be as follows

\frac{R_T_1}{R_T_2}=\frac{\rho_0(1+\alpha \cdot(T_1-2 0 )}{\rho_0(1+\alpha \cdot (T_2 -20 )}

\frac{0.25}{0.31}=\frac{1}{[1+\alpha(T-20)]}

1.24=1+\alpha (T-20)

0.24=\alpha(\ T -20 )

Putting\ the\ value\ of \alpha = 3.9 \times 10^-^3 DegC^-1

T = 81.52 Deg C

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3 years ago
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