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A scientist in a lab would like to determine if an object conducts electricity. Which of the following experiments would test th
2 answers:
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AS
work done =W = F.d = F d cosФ (Ф is angle between force F and displacement d) If a body/object is moving on a smooth surface (friction-less surface ) .There is no force acting on that body. F=0 so W=FdcosФ= (0)dcosФ ⇒ W=0
Now if a body is facing some amount of force but under the action of force there is no displacement covered. d=0 so W =FdcosФ= F(0)cosФ ⇒W=0
example: A person is applying a force on rigid wall but wall remains at rest there is no displacement occurs in wall.
The third term upon which work done dependent is angle between force and displacement i.e Ф. If Ф=90° then W= FdcosФ= Fdcos90⇒ W=0 ( as cos 90°=0)
Answer:
When both initial speed and initial displacement is doubled then amplitude will be doubled.
Explanation:
Given that :- Amplitude of simple harmonic Oscillator is doubled.
So,
Formula of Simple harmonic oscillator is ...........(1)
Where X = Position in (m,cm,km.....)
A = Amplitude in (m,cm,km.....)
F = Frequency in (Hz)
T = Time in (sec.)
Ф = Phase in (rad)
For initial displacement taking t=0 we get,
Initial displacement = .................(2)
Now taking equation (1) and differentiating it w.r.t to (t) we get
taking t=0 for initial speed then we get,
Initial speed = ...............(3)
observing equation (2) & (3) that the initial displacement and initial speed depends on the Amplitude of the Oscillator.
Hence,
when both initial speed and displacement is doubled then amplitude will be doubled.