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ladessa [460]
4 years ago
12

A scientist in a lab would like to determine if an object conducts electricity. Which of the following experiments would test th

is? A. Place the object on a source of heat, and measure the time it take to heat up. B. Float the object in water. C. Include the object in a circuit, and check to see if the circuit still works. D. Weight the object before and after refrigeration. ​
Physics
2 answers:
lubasha [3.4K]4 years ago
7 0

Answer: C. Include the object in a circuit

Explanation:

mr Goodwill [35]4 years ago
6 0

A scientist in a lab would like to determine if an object conducts electricity. How could he test this ?

A. <u>Place the object on a source of heat</u>, and measure the time it take to heat up.  <em>No.  This would  tell him how well the object conducts heat, but not electricity. </em>

B. <u>Float the object in water.</u>  <em>No.  This would tell him the object's density, and also maybe how well it can absorb water, but nothing about conducting electricity. </em>

<em>C. Include the object in a circuit,</em> and check to see if the circuit still works.  <em>YES !</em><em>  If the circuit still works, then the object conducts electricity.  If it doesn't then it doesn't. </em>

D. <u>Weight the object</u> before and after refrigeration.  <em>No.  This doesn't tell him much of anything ... there's no reason why the object should weigh more or weigh less when it's warm or cold.​</em>

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You are removing branches from your roof after a big storm. You throw a branch horizontally from your roof, which is a height 3.
mart [117]

Answer:

The initial velocity in the x-direction with which the branch was thrown is approximately 10.224 m/s

Explanation:

The given parameters of the motion of the branch are;

The height from which the branch is thrown = 3.00 m

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The direction in which the branch is thrown = Horizontally

Therefore, the initial vertical velocity of the branch, u_y = 0 m/s

The time it takes an object in free fall (zero initial downward vertical velocity) to reach the ground is given as follows;

s = u_y·t + 1/2·g·t²

Where;

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g = The acceleration due to gravity = 9.8 m/s²

∴ s = 0·t + 1/2·g·t² = 0 × t + 1/2·g·t² = 1/2·g·t²

t = √(2·s/g) = √(2 × 3/9.8) = (√30)/7 ≈ 0.78246

The horizontal distance covered before the branch touches the ground, x = 8.00 m

Therefore, the initial velocity in the horizontal, x-direction with which the branch was thrown, 'uₓ', is given as follows;

uₓ = x/t = 8.00 m/((√30)/7 s)

Using a graphing calculator, we get;

uₓ = 8.00 m/((√30)/7 s) = (28/15)·√30 m/s ≈ 10.224 m/s

The initial velocity in the horizontal, x-direction with which the branch was thrown, uₓ ≈ 10.224 m/s.

3 0
3 years ago
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