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ladessa [460]
4 years ago
12

A scientist in a lab would like to determine if an object conducts electricity. Which of the following experiments would test th

is? A. Place the object on a source of heat, and measure the time it take to heat up. B. Float the object in water. C. Include the object in a circuit, and check to see if the circuit still works. D. Weight the object before and after refrigeration. ​
Physics
2 answers:
lubasha [3.4K]4 years ago
7 0

Answer: C. Include the object in a circuit

Explanation:

mr Goodwill [35]4 years ago
6 0

A scientist in a lab would like to determine if an object conducts electricity. How could he test this ?

A. <u>Place the object on a source of heat</u>, and measure the time it take to heat up.  <em>No.  This would  tell him how well the object conducts heat, but not electricity. </em>

B. <u>Float the object in water.</u>  <em>No.  This would tell him the object's density, and also maybe how well it can absorb water, but nothing about conducting electricity. </em>

<em>C. Include the object in a circuit,</em> and check to see if the circuit still works.  <em>YES !</em><em>  If the circuit still works, then the object conducts electricity.  If it doesn't then it doesn't. </em>

D. <u>Weight the object</u> before and after refrigeration.  <em>No.  This doesn't tell him much of anything ... there's no reason why the object should weigh more or weigh less when it's warm or cold.​</em>

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Answer:

NADPH and ATP

Explanation:

In the clear stage the light that "hits" chlorophyll excites an electron to a higher energy level. In a series of reactions, energy is converted (throughout an electron transport process) into ATP and NADPH. Water breaks down in the process releasing oxygen as a secondary product of the reaction. ATP and NADPH are used to make the C-C bonds in the dark stage.

Photophosphorylation is the process of converting the energy of the electron excited by light into a pyrophosphate bond of an ADP molecule. This occurs when water electrons are excited by light in the presence of P680. The energy transfer is similar to the chemosmotic electron transport that occurs in the mitochondria.

Light energy causes the removal of an electron from a P680 molecule that is part of Photosystem II, the electron is transferred to an acceptor molecule (primary acceptor), and then passes downhill to Photosystem I through a conveyor chain of electrons The P680 requires an electron that is taken from the water by breaking it into H + ions and O-2 ions. These O-2 ions combine to form O2 that is released into the atmosphere.

The light acts on the P700 molecule of Photosystem I, causing an electron to be raised to a higher potential. This electron is accepted by a primary acceptor (different from the one associated with Photosystem II).

The electron goes through a series of redox reactions again, and finally combines with NADP + and H + to form NADPH, a carrier of H needed in the independent phase of light.

Electron of photosystem II replaces the excited electron of the P700 molecule.

There is therefore a continuous flow of electrons (non-cyclic) from water to NADPH, which is used for carbon fixation.

Cyclic electron flow occurs in some eukaryotes and in photosynthetic bacteria. NADPH does not occur, only ATP. This also occurs when the cell requires additional ATP, or when there is no NADP + to reduce it to NADPH.

In Photosystem II, the "pumping" of H ions into the thylakoids (from the stroma of the chloroplast) and the conversion of ADP + P to ATP is motorized by an electron gradient established in the thylakoid membrane.

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3 years ago
Question 1 of 10
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Answer:

C. 5.6 × 10^11 N/C

Explanation:

The electric field E at a distance R from a charge Q is given by

E = k\dfrac{Q}{R^2}

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therefore,

E = (9*10^9)\dfrac{0.0035C}{(0.0075m)^2}

\boxed{E = 5.6*10^{11}N/C.}

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