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ella [17]
3 years ago
6

What information is needed to determine the energy of an electron in a many-electron atom? Check all that apply. What informatio

n is needed to determine the orientation of orbital? What information is most important in determining the size of an orbitaI? What information is needed to determine the general shape of an orbital?
Chemistry
1 answer:
Leviafan [203]3 years ago
5 0

Answer:

n and l

m

n

m

Explanation:

<em>What information is needed to determine the energy of an electron in a many-electron atom?</em>

We need to know the principal quantum number (n) and the angular quantum number (l). The higher the n, the more energy the electron has. For the same n, the higher the l, the more energy the electron has.

<em />

<em>What information is needed to determine the orientation of orbital?</em>

We need to know the magnetic quantum number (m). For instance, in an orbital s, m can only take the value 0, because there is only one possible orientation. In p orbitals, m can take the values -1, 0 and -1, which reflects the 3 possible orientations.

<em>What information is most important in determining the size of an orbitaI?</em>

The size of an orbital depends on the principal quantum number (n). The higher the n, the larger the orbital.

<em>What information is needed to determine the general shape of an orbital?</em>

The general shape of an orbital is determined by the angular quantum number (l). When l takes the value 0, the orbital is "s" (spheric). When l takes the value 1, the orbital is "p" (lobed shape), etc.

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In the embden-meyerhof pathway, one mole of _____ is converted into two moles of pyruvic acid.
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3 years ago
What is the difference between 13.254 m/s and 7.7 m/s? Round your answer to the correct number of significant digits.
tresset_1 [31]

Answer:

5.6 m/s

Explanation:

Given,

First number = 13.254 m/s

Second number = 7.7 m/s

We need to find the difference between these two numbers. First we round off 13.254 to one decimal place i.e. 13.254 = 13.3 m/s

The difference between them is given by :

D = 13.3 - 7.7

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3 years ago
which solution would help local farms if the water level in a reservoir used for irrigation became low?​
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7 0
3 years ago
Read 2 more answers
Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 3.00 molesmoles of aluminum sulfate, Al2(SO4)3Al2(SO4)3.
STatiana [176]

Answer:

n_{Al}=6.00molAl\\\\n_{S}=9.00molS\\\\n_{O}=36.0molO

Explanation:

Hello!

In this case, when analyzing the moles of an element inside a compound, we need to keep in mind that a mole ratio should be set up; thus, for aluminum sulfate, we have the following ones:

\frac{2molAl}{1molAl_2(SO_4)_3} \\\\\frac{3molS}{1molAl_2(SO_4)_3} \\\\\frac{12molO}{1mol1molAl_2(SO_4)_3}

Thus, starting by 3.00 moles of aluminum sulfate, the moles of each element turn out:

n_{Al}=3.00molAl_2(SO_4)_3*\frac{2molAl}{1molAl_2(SO_4)_3} =6.00molAl\\\\n_{S}=3.00molAl_2(SO_4)_3*\frac{3molS}{1molAl_2(SO_4)_3} =9.00molS\\\\n_{O}=3.00molAl_2(SO_4)_3*\frac{12molO}{1molAl_2(SO_4)_3}=36.0molO

Best regards!

3 0
3 years ago
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