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4 years ago

14

Neglecting air resistance, if a package is dropped from an airplane flying 100 km/hr at an altitude of 200 meters, how far from

the drop point would the package land? Give answer in meters.

1 answer:

UkoKoshka [18]4 years ago

4 0

Answer:

178 m

Explanation:

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What is the power involved in lifting a 1.0-kg object 1.0 m in 1.0 s??

MAVERICK [17]

Mass = 1kg
Distance = 1m
Time = 1s
Force= Mass x Acceleration due to graviy
          = 1 x 9.8 = 9.8
Velocity = Distance / time
              = 1 / 1 =1m/s
Power = Force x velocity
           = 9.8 x 1 = 9.8 W

5 0

3 years ago

An astronaut is being tested in a centrifuge. The centrifuge has a radius R and, in starting, rotates according to θ = tn, where

Igoryamba

Answer:

a) ω=n

b) V = R*n

c) a = 0

d) $ar = R*n^2$

Explanation:

Angular velocity is given by the derivative of θ:

ω = n

Linear Velocity will be:

V = ω*R = n*R

Tangential acceleration will be the derivative of the linear velocity. Since velovity is constant:

a = 0

Radial acceleration is given by:

$ar = V^2/R = (R*n)^2/R=R*n^2$

4 0

4 years ago

On a sunny day, you and a friend are relaxing on the grass at a park. Your find says that the sun shines while light on the park

nikitadnepr [17]

Answer:

i do agree to my friend

Explanation:

White light is absorbed by the callours that are not white. if it was white it would of been reflected. The light also helps us to see the object i.e the grass as the light is shining on it.

i hope your happy :)

7 0

3 years ago

Read 2 more answers

A particle moving at 10 m/s along the x-axis collides elastically with another particle moving at 5.0 m/s in the same direction

drek231 [11]

Explanation:

It is given that,

Velocity of particle 1, u₁ = 10 m/s

Velocity of particle 2, u₂ = 5 m/s

Let v₁ and v₂ are the final speed of both particles after the collision. Applying the conservation of momentum as :

$mu_1+mu_2=mv_1+mv_2$

$15=v_1+v_2$ ......................(1)

For an elastic collision, the coefficient of restitution is equal to 1 as :

$\dfrac{v_2-v_1}{u_1-u_2}=1$

$\dfrac{v_2-v_1}{5}=1$

${v_2-v_1}=5$ ................(2)

On solving equation (1) and (2), we get,

$v_1=5\ m/s$

$v_2=10\ m/s$

So, the speeds of particle 1 and particle 2 after the collision is 5 m/s and 10 m/s respectively. Hence, this is the required solution.

8 0

3 years ago

What happens to the wavelength of a wave on a string when the frequency is doubled

frozen [14]

Answer:

$\lambda'=\dfrac{1}{2}\times \lambda$

Explanation:

The number of oscillation per unit time is called frequency of a wave while the distance between two consecutive crests and the trough is called its wavelength.

The wavelength of a wave is given by :

$\lambda=\dfrac{v}{f}$

If frequency is doubled, f' = 2f

$\lambda'=\dfrac{v}{f'}$

$\lambda'=\dfrac{v}{2f}$

$\lambda'=\dfrac{1}{2}\times \dfrac{v}{f}$

$\lambda'=\dfrac{1}{2}\times \lambda$

So, when the frequency is doubled the wavelength of a wave on the string becomes half.

5 0

4 years ago