Question

How many oh- ions are present in 3.00 mol of ca(oh)2?

Answer 1

Here is the work for the answer which is 3.61 x 10^24 OH- ions :)

Answer 2

Answer: The number of $OH^-$ ions present in given amount of calcium hydroxide is $3.6132\times 10^{24}$

Explanation:

Equation representing ionization of calcium hydroxide follows:

$Ca(OH)_2\rightarrow Ca^{2+}+2OH^-$

$Ca(OH)_2$ is a base which releases 2 hydroxide ions $(OH^-)$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules of ions.

So, 3 moles of $Ca(OH)_2$ will contain $3\times 2\times 6.022\times 10^{23}=36.132\times 10^{23}=3.6132\times 10^{24}$ number of $OH^-$ ions

Hence, the number of $OH^-$ ions present in given amount of calcium hydroxide is $3.6132\times 10^{24}$