Answer: The complement components that is the direct cause of the enhanced vascular permeability and chemoattraction in the abraded skin area in this experiment is C5a. The correct option is C.
Explanation:
When the investigator gently abrades the skin from the flank of a mouse, creating a 1 × 2-cm skin window, the investigator caused a mild tissue damage which leads to a complex series of events resulting in the repair of the damaged tissue. These events are collectively called an INFLAMMATION. Inflammation can therefore be defined as the reaction of vascularized living tissue to local injury.
There are many compounds that triggers specific aspects of inflammation and they are collectively called inflammatory mediators. An example is the Complement component 5a. It has the following functions in mediating inflammatory response:
- enhances vascular permeability
- it has the ability to attract other cells to the site of the abraded skin area (a chemoattractant).
<span>The heating of the metal would result in an energy expenditure
</span>that would make mining copper counterproductive
<span>The expenditure of the process is comparative
to how much material (rock, dirt, whatever) you have to process. The more will
be the material to be route, the larger will be the equipment, or the longer you have
to run it, and the more power and other other materials you need. so that is why its expensive to extract copper from contaminated lan</span>
<span>hope it helps</span>
<span>hope it helps</span>
Answer : At temperatures greater than this reaction is spontaneous under standard conditions.
Explanation : Given,
= 131.3 KJ/mole = 131300 J/mole
= 127.6 J/mole.K
Gibbs–Helmholtz equation is :
As per question the reaction is spontaneous that means the value of is negative or we can say that the value of is less than zero.
The above expression will be:
Now put all the given values in this expression, we get :
Therefore, at temperatures greater than this reaction is spontaneous under standard conditions.
Answer:
34 g of NH₃ were produced in the reaction
Explanation:
N₂ (g) + 3H₂ (g) → 2NH₃ (g)
Moles of N₂ → 28 g / 28 g/m = 1 mol
Moles of H₂ → 25g / 2 g/m = 12.5 moles
Clearly, the limiting is the nitrogen.
1 mol of N₂ produced 2 moles of ammonia
So, If I have 1 mol, I'll produce the same amount
2 moles of NH₃ = Mol . Molar mass
2 m . 17 g/m = 34 g