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artcher [175]
3 years ago
7

What is the molar mass of chromic sulfate, Cr2(SO4)3?

Chemistry
1 answer:
mestny [16]3 years ago
4 0

Answer:

392.16 g/mol

Explanation:

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PLEASE HELP ITS MAJOR
Charra [1.4K]

Answer:

solid, liquid

Explanation:

solid liquid and gas are the three most common states of matter, my best guessstimation is that solid is the ¨normal form¨ with you having to then heat it up to get to gas or, change it to liquid... even though most of the earth is liquid soo it could also be liquid try your best and think it over

3 0
2 years ago
Read 2 more answers
What is the density of ice
amm1812
The density of ice is 0.9167 g/cm<span>3</span>
5 0
3 years ago
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If the solubility of a gas in water at 25°C is 22.25 mg/L at 2.5 atm of pressure, what is its solubility (in mg/L) at 25°C
tamaranim1 [39]

Answer:

8.9 mg/l

Explanation: Temp doesnt matter so throw that out automatically then your equation is;

S1/P1=S2/P2

We are looking for S2 and that equation is;

S2=S1*P2/P1 and that is S2=22.25*1/2.5

A little bit of simple math and you get your answer: 8.9 mg/l

8 0
2 years ago
Which best defines color?
katrin [286]

Answer:

its A

Explanation:

The definition of color is a component of light which is separated when it is reflected off of an object. The appearance of objects or light sources described in terms of the individual's perception of them, involving hue, lightness, and saturation for objects, and hue, brightness, and saturation for light sources.

5 0
2 years ago
A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0
OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2C_2O_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL

Putting values in above equation, we get:

2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0
2 years ago
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