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Bogdan [553]
3 years ago
6

A particular experiment requires 13.5 µl hydrochloric acid solution. if 250 ml hydrochloric acid solution is available, how many

times can the experiment be performed
Chemistry
2 answers:
ladessa [460]3 years ago
6 0
The amount of HCl required for one experiment - 13.5 µl 
the volume in terms of L - 13.5 x 10⁻⁶ L
the volume of HCl available - 0.250 L 
since one experiment uses up - 13.5 x 10⁻⁶ L 
then number of experiments - 0.250 L / 13.5 x 10⁻⁶ L  = 1.8 x 10⁴ times 
the experiment can be carried out 18000 times 
aivan3 [116]3 years ago
6 0

Answer:

b) 18,500

I just did the lesson and this is what they said was right.

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Calculate molality,molarity and mole fraction of KI if the density of 20%(mass) aqueous KI is 1.202 g/mL
Scorpion4ik [409]
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2FeCl3 ---&gt; 2FeCl2 + Cl2
vesna_86 [32]
The correct options are as follows: 
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2. In the reaction given above, the chlorine atom is OXIDIZED.
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3. This type of redox reaction can not take place. This is because, in chemical reaction, the chlorine atom is always looking for another element that will donate an electron to it in order to become stable. Thus, chlorine atom easily gain electrons but it can not donate an electron to another element.<span />
8 0
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Read 2 more answers
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