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Bogdan [553]
3 years ago
6

A particular experiment requires 13.5 µl hydrochloric acid solution. if 250 ml hydrochloric acid solution is available, how many

times can the experiment be performed
Chemistry
2 answers:
ladessa [460]3 years ago
6 0
The amount of HCl required for one experiment - 13.5 µl 
the volume in terms of L - 13.5 x 10⁻⁶ L
the volume of HCl available - 0.250 L 
since one experiment uses up - 13.5 x 10⁻⁶ L 
then number of experiments - 0.250 L / 13.5 x 10⁻⁶ L  = 1.8 x 10⁴ times 
the experiment can be carried out 18000 times 
aivan3 [116]3 years ago
6 0

Answer:

b) 18,500

I just did the lesson and this is what they said was right.

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Answer:

2.5284 x 10^24

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3 years ago
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4 years ago
Matter has mass and takes up ______________. The amount of space that matter
svlad2 [7]
Answer:
space

Explanation:
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6 0
2 years ago
Draw the lewis structure for so42-. How many equivalent resonance structures can be drawn?
Elena-2011 [213]

Answer : The Lewis-dot structure and resonating structure of SO_4^{2-} is shown below.

Explanation :

Resonance structure : Resonance structure is an alternating method or way of drawing a Lewis-dot structure for a compound.

Resonance structure is defined as any of two or more possible structures of the compound. These structures have the identical geometry but have different arrangements of the paired electrons. Thus, we can say that the resonating structure are just the way of representing the same molecule.

First we have to determine the Lewis-dot structure of SO_4^{2-}.

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, SO_4^{2-}

As we know that sulfur and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in SO_4^{2-} = 6 + 4(6) + 2 = 32

According to Lewis-dot structure, there are 12 number of bonding electrons and 20 number of non-bonding electrons.

Hence, the Lewis-dot structure and resonating structure of SO_4^{2-} is shown below.

8 0
4 years ago
Calculate the ph of a 0.005 m solution of potassium oxide k2o
Alecsey [184]
First, we have to see how K2O behaves when it is dissolved in water:

K2O + H20 = 2 KOH

According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:

c(KOH) : c(K2O) = 1 : 2

So,

c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)

Now we can calculate pH:

pOH= -log c(OH⁻) = -log 0.01 = 2

pH= 14-2 = 12




3 0
3 years ago
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