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3 years ago

Use the graph below to answer the following question: What does the straight, diagonal line represent?

Physics

1 answer:

slamgirl [31]3 years ago

4 0

Answer:

The straight, diagonal line represent a tangent line

Explanation:

As the shown straight diagonal line represented in the figure just goes by touching a part or points on the curve, this line will be termed as tangent line. A secant line is the one which joins two points on the curve in the inward side. But in this case, the line is touching the outward points of the curve. Also the line is sliding through the curve in outward points. So this kind of line touching some points on any curve is termed as tangential line or slope of that curve.

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how many bits are required to sample an incoming signal 4000 times per second using 64 different amplitude level

Gelneren [198K]

Answer:

6 bits

Explanation:

The quality of digitized signal can be improved by reducing quantizing error. This is done by increasing the number of amplitude levels, thereby minimizing the difference between the levels and hence producing a smoother signal.

Also, Sampling frequently (also known as oversampling) can help in improving signal quality.

To get the number of bits, we use:

2ⁿ = amplitude level

where n is the number of bits.

Given an amplitude level of 64, hence:

2ⁿ = 64

2ⁿ = 2⁶

n = 6 bits

6 0

3 years ago

You throw a ball with a mass of 0.50 kg against a brick wall. It hits the wall moving horizontally to the left at 20 m/s and reb

Orlov [11]

Answer:

The value of impulse of the net force on the ball during its collision with wall is $I = 15\ kg \frac{m}{s}$

The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N

Explanation:

Mass of the ball = 0.5 kg

Horizontal velocity $V_{x}$ = 20 $\frac{m}{s}$

Velocity after collision $V_{-x}$ = - 10 $\frac{m}{s}$

(A). Impulse of the net force on the ball during its collision with wall is

$I = m (V_{x} - V_{-x})$

I = 0.5 × (20 + 10)

$I = 15\ kg \frac{m}{s}$

This is the value of impulse of the net force on the ball during its collision with wall.

(B). The magnitude of average horizontal force

$F = \frac{I}{T}$

Where F = Force

I = impulse & t = time interval = 0.001 sec

$F = \frac{15}{0.001}$

F = 15000 N

This is the value of average horizontal force that the wall exerts on the ball during the impact.

8 0

3 years ago

A student throws a set of keys vertically upward to her sorority sister, who is in a window 3.50 m above. The second student cat

Mkey [24]

Answer:

a) 8.58 m/s upward

b) -2.211 m/s downward

Explanation:

Let gravitational acceleration g = -9.81m/s2. This is negative because it deceleration the upward motion of the key.

(a)We have the following equation of motion

$s = v_0t + gt^2/2$

where $v_0$ is the initial upward velocity of the keys, t = 1.1s is the time it takes for the keys to travel a distance of s = 3.5 m

$3.5 = v_01.1 - 9.81*1.1^2/2$

$3.5 = 1.1v_0 - 5.94$

$1.1v_0 = 3.5 + 5.94 = 9.44$

$v_0 = 9.44 / 1.1 = 8.58 m/s$

So the keys were thrown initially upward with a speed of 8.58 m/s

(b) If the initial velocity of the key is 8.58 m/s and it is subjected to a deceleration of 9.81m/s2 for 1.1s then the velocity right at the 1.1s instant is

$v = v_0 + gt = 8.58 - 9.81*1.1 = -2.211 m/s$

So they keys would have a downward speed of 2.211 m/s

5 0

3 years ago

1.) Using Ohm’s law, explain how voltage changes in relation to current, assuming that resistance remains constant.

Harrizon [31]

1.) Ohm's law is understood as I = V/R. Given that resistance is constant, then voltage changes directly proportional to current.

2.) The more current that passes through a lightbulb, the brighter it glows. The higher the current, the higher the power, where power determines the brightness of a bulb.

3.) A bulb has a specific limit to how much power (Watts) it can handle. Going over the limit would cause the bulb to burn out.

4.) When a bulb burns out, no current will be able to pass through the filament.

4 0

3 years ago

Read 2 more answers

An object is in circular motion how will the object behave if the centripetal force is removed

Monica [59]

If the force is removed, then there are no other forces acting on the object, the object will continue to move at constant velocity, meaning that it would move in a line tangent to the circular path.

8 0

4 years ago