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jekas [21]
3 years ago
11

You apply a 56.3N force to a 4.2Kg cart towards the right. The cart accelerates towards the right at a rate of 0.8m/s2. What is

the magnitude, in Newtons, of the net frictional force (the sum of the only other forces, besides the 56.3N one you apply)? Please enter only a numerical answer, no units necessary.
Physics
1 answer:
vovangra [49]3 years ago
6 0

Answer:

52,94N

Explanation:

Frictional force is the opposing force that is created between two surfaces that try to move in the same direction or that try to move in opposite directions. The main purpose of a frictional force is to create resistance to the motion of one surface over the other surface.

Calculation:

Le the value of frictional force be Fk, therefore acceleration a = (F- Fk)/m

where :

F is the applied force

m the mass of the cart

a = (F- Fk)/m = 0.8

F - Fk = 0.8m

Fk = F - 0.8m

Fk = 56.3 - (0.8×4.2)

Fk = 52.94 N

The magnitude, in Newtons, of the net frictional force is therefore 52.94N

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This talks about the weather

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A horizontal spring with spring constant 950 N/m is attached to a wall. An athlete presses against the free end of the spring, c
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Answer:

66.5N

Explanation:

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An airplane flying at an altitude of 6 miles passes directly over a radar antenna. When the airplane is 10 miles away (s = 10),
Novosadov [1.4K]

Answer:

Explanation:

Given

altitude of the Plane h=6\ miles

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2h\frac{\mathrm{d} h}{\mathrm{d} t}+2x\frac{\mathrm{d} x}{\mathrm{d} t}=2s\frac{\mathrm{d} s}{\mathrm{d} t}

as altitude is not changing therefore \frac{\mathrm{d} h}{\mathrm{d} t}=0

0+x\frac{\mathrm{d} x}{\mathrm{d} t}=s\frac{\mathrm{d} s}{\mathrm{d} t}

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5 0
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Sergio [31]

Answer:

* Larger mirrors collect more light and therefore fainter and more distant objects can have enough intensity to be detected

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Refracting telescopes get bigger every day for two main reasons.

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