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zmey [24]
3 years ago
15

To analyze and design a passive, first-order high-pass filter using a series RC circuit. An instrument needs to detect periodic

signals of approximately 5000 Hz. The instrument operates in an environment with a lot of periodic noise ranging from a few to several hundred hertz. A high-pass RC filter can be built using available 1.0 μF capacitors; resistors of any necessary value are also available.
1. Using the available 1.0 μF capacitor, what is the value of the resistor needed to make a high-pass filter with a cutoff frequency of 3000 Hz? Express your answer to three significant figures and include appropriate units
Engineering
1 answer:
olga nikolaevna [1]3 years ago
6 0

Answer:

R= 53.7 Ω

Explanation:

fc= 1/(2πRC)

3000=1/(2π× 1 × 10^-6 × R)

R= 53.7 Ω

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A woodcutter wishes to cause the tree trunk to fall uphill, even though the trunk is leaning downhill. With the aid of the winch
Sedbober [7]

Answer:

The correct answer will be "400.4 N". The further explanation is given below.

Explanation:

The given values are:

Mass of truck,

m = 600 kg

g = 9.8 m/s²

On equating torques at the point O,

⇒  T\times Cos(10+5)\times (1.3+4)=mg\times Sin(5)\times 4

So that,

On putting the values, we get

⇒  T\times Cos(15^{\circ})\times 5.3=600\times 9.8\times Sin(5^{\circ})\times 4

⇒                             T=400.4 \ N

8 0
3 years ago
1. In a series circuit the sum of all voltage drops produced by the loads in the circuit
GarryVolchara [31]

Answer:

ik the answer but I'm busy rn

5 0
2 years ago
HELP<br><br><br>the overall width of a part is dimensioned as 3.00 ± 0.02. what is the tolerance
MariettaO [177]

Answer:

Not knowing the units the tolerance is 0.02.  I would presume mm but hopefully your question has more detail.  

Explanation:

The tolerance is the portion after the main dimension (+/- 0.02).  In our case we have bilateral tolerance since there is tolerance in both directions (positive and negative).  If you were building a part the acceptable range would be 2.98 to 3.02 based on the tolerance provided.  

3 0
3 years ago
Read 2 more answers
An object whose mass is 251 kg is located at an elevation of 24 m above the surface of the earth. For g-9.78 ms, determine the g
Harlamova29_29 [7]

Answer:

Gravitational Potential =58.914 KJ

Explanation:

We know that

Gravitational Potential Energy = mass\times g\times Height

Given mass = 251 kg

Height= 24 m

g is acceleration due to gravity = 9.78m/s^{2}

Applying values in the equation we get

Gravitational Potential Energy=251X9.78X24 Joules

Gravitational Potential Energy=58914.72 Joules

Gravitational Potential Energy =\frac{58914.72}{1000}KJ= 58.914KJ

4 0
3 years ago
Given below are the measured streamflows in cfs from a storm of 6-hour duration on a stream having a drainage area of 185 mi^2.
sertanlavr [38]

Answer:

33.56 ft^3/sec.in

Explanation:

Duration = 6 hours

drainage area = 185 mi^2

constant baseflow = 550 cfs

<u>Derive the unit hydrograph using the inverse procedure </u>

first step : calculate for the volume of direct runoff hydrograph using the details in table 2 attached below

Vdrh = sum of drh *  duration

        = 29700 * 6 hours ( 216000 secs )

        = 641,520,000 ft^3.

next step : Calculate the volume of runoff in equivalent depth

Vdrh / Area = 641,520,000  / 185 mi^2

                    = 1.49 in

Finally derive the unit hydrograph

Unit of hydrograph = drh /  volume of runoff in equivalent depth

                                = 50 ft^3 / 1.49 in  =  33.56 ft^3/sec.in

5 0
3 years ago
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