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r-ruslan [8.4K]
4 years ago
3

Two carts are initially moving to the right on a low-friction track, with cart 1 behind cart 2. Cart 1 has a speed twice that of

cart 2 and so moves up and rear-ends cart 2, which has twice the inertia of cart 1. Part A Suppose that the the initial speed of cart 2 is v. What is the speed of cart 1 right after the collision if the collision is elastic?
Physics
1 answer:
Alexxx [7]4 years ago
4 0

Answer:

Explanation:

Given

cart 1 has twice the speed of cart 2

cart 2 has twice the mass of cart 1

Suppose m is the mass of cart 1 so mass of cart 2 is 2 m

suppose u is the initial velocity of car 2 so initial velocity of car 1 is u

For Elastic collision velocity after collision is given by

velocity of cart 2 is v_2=\frac{2m_1}{m_1+m_2}\cdot u_1-\frac{m_1-m_2}{m_1+m_2}\cdot u_2

velocity of cart 1 is v_1=\frac{m_1-m_2}{m_1+m_2}\cdot u_1+\frac{2m_2}{m_1+m_2}\cdot u_2

here m_1=m,m_2=2 m

u_1=2u,u_2=u

substituting values we get

v_1=\frac{m-2m}{3m}\cdot 2u+2\cdot \frac{2m}{3m}\cdot u

v_1=\frac{2u}{3}

v_2=\frac{2m}{3m}\cdot (2u)-\frac{m-2m}{3m}\cdot u

v_2=\frac{5u}{3}

               

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