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Alla [95]
3 years ago
14

When a 60 Hz sinusoidal voltage is applied to the input of a half-wave rectifier, the output frequency is

Engineering
1 answer:
Ludmilka [50]3 years ago
4 0

Answer:

120 Hz

Explanation:

Given that a 60 Hz sinusoidal voltage is applied to the input of a half-wave rectifier, what will be the output frequency ?

Ideally, the supply frequency will be equal to the ripple frequency.

But in a half - way rectifier, the out put frequency is twice the input sinusoidal voltage frequency.

The output frequency = 2 × 60

Output frequency = 120 Hz

Therefore, When a 60 Hz sinusoidal voltage is applied to the input of a half-wave rectifier, the output frequency is 120 Hz.

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Which sentence is correct about the exergy of an empty (pressure around zero Pascal) tank with a volume of V, located in an envi
sineoko [7]

Answer:

The correct option is;

c.  the exergy of the tank can be anything between zero to P₀·V

Explanation:

The given parameters are;

The volume of the tank = V

The pressure in the tank = 0 Pascal

The pressure of the surrounding = P₀

The temperature of the surrounding = T₀

Exergy is a measure of the amount of a given energy which a system posses that is extractable to provide useful work. It is possible work that brings about equilibrium. It is the potential the system has to bring about change

The exergy balance equation  is given as follows;

X_2 - X_1 = \int\limits^2_1 {} \, \delta Q \left (1 - \dfrac{T_0}{T} \right ) - [W - P_0 \cdot (V_2 - V_1)]- X_{destroyed}

Where;

X₂ - X₁ is the difference between the two exergies

Therefore, the exergy of the system with regards to the environment is the work received from the environment which at is equal to done on the system by the surrounding which by equilibrium for an empty tank with 0 pressure is equal to the product of the pressure of the surrounding and the volume of the empty tank or P₀ × V less the work, exergy destroyed, while taking into consideration the change in heat of the system

Therefore, the exergy of the tank can be anything between zero to P₀·V.

6 0
3 years ago
The temperature of a system rises by 10 °C during a heating process. Express the rise in temperature of K, R, and °F.
Lorico [155]

Explanation:

Given T = 10 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (10 + 273.15) K = 283.15 K

<u>T = 283.15 K </u>

The conversion of T( °C) to T(F) is shown below:

T (°F) = (T (°C) × 9/5) + 32  

So,

T (°F) = (10 × 9/5) + 32 = 50 °F

<u>T = 50 °F</u>

The conversion of T( °C) to T(R) is shown below:

T (R) = (T (°C) × 9/5) + 491.67

So,

T (R) = (10 × 9/5) + 491.67 = 509.67 R

<u>T = 509.67 R</u>

6 0
3 years ago
Of the cost reduction strategies for workers' compensation mentioned in the required readings, which one do you think would work
Vesnalui [34]

In industries together with production, we want people to address the manufacturing of merchandise and the usage of heavy machinery.

<h3>What is the painting situation?</h3>

In such painting situations, people are at risk of injuries, and this prices the maximum for the company. So so that you can put into effect value discount is such conditions we want to have right coincidence cowl plans for the people and make sure all of the protection precautions are taken withinside the factory.

  1. The people have to be properly educated on using protection measures and in case any injuries arise we have to have coverage claims in order that we not want to make investments extra cash and we also can offer protection and protection to the people.
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3 0
1 year ago
Can crushers help us recycle in a space efficient way which is good for saving the earth and for giving you more room in your ap
777dan777 [17]

Answer:

Force magnitude = 296.7 N

Explanation:

Detailed illustration is given in the attached document.

6 0
3 years ago
Knowing that v = –8 m/s when t = 0 and v = 8 m/s when t = 2 s, determine the constant k. (Round the final answer to the nearest
docker41 [41]

Answer:

a)We know that acceleration a=dv/dt

So dv/dt=kt^2

dv=kt^2dt

Integrating we get

v(t)=kt^3/3+C

Puttin t=0

-8=C

Putting t=2

8=8k/3-8

k=48/8

k=6

5 0
3 years ago
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