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Alla [95]
3 years ago
14

When a 60 Hz sinusoidal voltage is applied to the input of a half-wave rectifier, the output frequency is

Engineering
1 answer:
Ludmilka [50]3 years ago
4 0

Answer:

120 Hz

Explanation:

Given that a 60 Hz sinusoidal voltage is applied to the input of a half-wave rectifier, what will be the output frequency ?

Ideally, the supply frequency will be equal to the ripple frequency.

But in a half - way rectifier, the out put frequency is twice the input sinusoidal voltage frequency.

The output frequency = 2 × 60

Output frequency = 120 Hz

Therefore, When a 60 Hz sinusoidal voltage is applied to the input of a half-wave rectifier, the output frequency is 120 Hz.

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1 import java.util.Scanner; 3 public class EqualityAndRelational { 4 public static void main (String args) args) { int userBonus
Anastaziya [24]

Missing Part of the Question

Complete the expression so that userPoints is assigned with 0 if userBonus is greater than 20 (second branch). Otherwise, userPoints is assigned with 10 (first branch

import java.util.Scanner;

public class EqualityAndRelational {

public static void main (String args) args) {

int userBonus; int userPoints;

userPoints=0;

Scanner scnr = new Scanner(System.in);

userBonus = scnr.nextInt();

// Program will be tested with values : 15, 20, 25, 30, 35. 12 13 14 15 16 17 18 19

( Your solution goes here)

{

userPoints= 10 ;

}

else {

userPoints = 0;

}

}

}

Answer;

Replace

( Your solution goes here)

With

if(userBonus>20).

The full program becomes

import java.util.Scanner;

public class EqualityAndRelational {

public static void main (String args) args) {

int userBonus; int userPoints;

userPoints=0;

Scanner scnr = new Scanner(System.in);

userBonus = scnr.nextInt();

// Program will be tested with values : 15, 20, 25, 30, 35. 12 13 14 15 16 17 18 19

if(userBonus>20)

{

userPoints= 10 ;

}

else {

userPoints = 0;

}

}

}

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