1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fynjy0 [20]
3 years ago
6

the speed of sound in the air is about 340m/s. what is the wavelength of a sound wave with a frequency of 400Hz?

Physics
1 answer:
olga2289 [7]3 years ago
5 0

Wavelength = (speed) / (frequency)

Wavelength = (340 m/s) / (400 /s)

<em>Wavelength = 0.85 meter</em>

You might be interested in
The ratio of present ages of sunanya
kykrilka [37]

hope it helps

plz mark brainliest

4 0
3 years ago
Block B is attached to a massless string of length L = 1 m and is free to rotate as a pendulum. The speed of block A after the c
Amanda [17]

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The minimum velocity of A is  v_A= 4m/s

Explanation:

From the question we are told that

    The length of the string is  L = 1m

     The initial speed of block A is u_A

     The final speed of block A is  v_A = \frac{1}{2}u_A

      The initial speed of block B is u_B = 0

      The mass of block A  is  m_A = 7kg  gh

      The mass of block B is  m_B  = 2 kg

According to the principle of conservation of momentum

       m_A u_A + m_B u_B = m_Bv_B + m_A \frac{u_A}{2}

Since block B at initial is at rest

       m_A u_A  = m_Bv_B + m_A \frac{u_A}{2}

      m_A u_A  - m_A \frac{u_A}{2} = m_Bv_B

          m_A \frac{u_A}{2} = m_Bv_B

  making v_B the subject of the formula

             v_B =m_A \frac{u_A}{2 m_B}

Substituting values

               v_B =\frac{7 u_A}{4}  

This v__B is the velocity at bottom of the vertical circle just at the collision with mass A

Assuming that block B is swing through the vertical circle(shown on the second uploaded image ) with an angular velocity  of v__B' at  the top of the vertical circle  

 The angular centripetal acceleration  would be mathematically represented

                   a= \frac{v^2_{B}'}{L}

Note that  this acceleration would be toward the center of the circle

      Now the forces acting at the top of the circle can be represented mathematically as

         T + mg = m \frac{v^2_{B}'}{L}

    Where T is the tension on the string

  According to the law of energy conservation

The energy at  bottom of the vertical circle   =  The energy at the top of

                                                                                the vertical circle

   This can be mathematically represented as

                 \frac{1}{2} m(v_B)^2 = \frac{1}{2} mv^2_B' + mg 2L

From above  

                (T + mg) L = m v^2_{B}'

Substitute this into above equation

             \frac{1}{2} m(\frac{7 v_A}{4} )^2 = \frac{1}{2} (T + mg) L  + mg 2L  

             \frac{49 mv_A^2}{16}  = \frac{1}{2} (T + mg) L + mg 2L

          \frac{49 mv_A^2}{16}  = T + 5mgL

The  value of velocity of block A needed to cause B be to swing through a complete vertical circle is would be minimum when tension on the string due to the weight of B is  zero

        This is mathematically represented as

                      \frac{49 mv_A^2}{16}  = 5mgL

making  v_A the subject

            v_A = \sqrt{\frac{80mgL}{49m} }

substituting values

          v_A = \sqrt{\frac{80* 9.8 *1}{49} }

              v_A= 4m/s

     

6 0
3 years ago
With what velocity Must a 0.53 kg softball be moving to be equal to the momentum of a 0.31 kg baseball moving at 21 m/s
vladimir2022 [97]

Answer:12.28m/s

Explanation:

momentum of baseball =mass of baseball x velocity of baseball

Momentum of baseball =0.31x21

Momentum of baseball =6.51kgm/s

For a softball to have same momentum with the baseball we can say :momentum of baseball =mass of softball x velocity of softball

6.51=0.53 x velocity of softball

Velocity of softball =6.51/0.53

Velocity of softball =12.28m/s

3 0
3 years ago
a Car with a mass of 2000 kg is moving around a circular curve at a uniform velocity of 25 m/s the curve has a radius of 80 m wh
Viefleur [7K]
Well, first of all, the car is not moving at a uniform velocity, because,
on a curved path, its direction is constantly changing.  Its speed may
be constant, but its velocity isn't.

The centripetal force on a mass 'm' that keeps it on a circle with radius 'r' is

             F = (mass) · (speed)² / (radius).

For this particular car, the force is

                    (2,000 kg) · (25 m/s)² / (80 m)

                 = (2,000 kg) · (625 m²/s²) / (80 m)

                 = (2,000 · 625 / 80)  (kg · m / s²)

                 =              15,625  newtons .
5 0
3 years ago
White light passes through a yellow stained glass window onto the floor. What color flashlight can you shine to create a white s
wolverine [178]
Yesssssssssssssssssss I can
8 0
3 years ago
Other questions:
  • the number of electrons in a copper penny is approximately 10 10^23. How large would the force be on an object if it carried thi
    12·1 answer
  • How does the movement of particles of matter change when matter goes from solid to liquid?
    10·1 answer
  • Four students measure the mass of a standard mass that has an accepted value of 150.0 g. They post their results in a table.
    15·1 answer
  • Exercise combined with a blank can help control weight
    11·1 answer
  • What is meant by the period of a pendulum?
    14·1 answer
  • A) In terms of electrolysis, it’s been said from multiple sources online that “Using water's density and relative atomic populat
    13·1 answer
  • Queremos diseñar un montacargas que pueda subir con una rapidez de 12 km/h una mas 700 kg hasta 40 m de altura en un minuto. Cal
    7·1 answer
  • What explains the difference in appearance between a full moon and a new moon?Select all that apply.
    15·1 answer
  • What is a conservative force?
    5·1 answer
  • What is the kinetic energy of a 14kg object traveling at 10m/s
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!