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3 years ago

15

Which of the following represents a case in which you are not accelerating?a. Driving in a straight line at 60 miles per hr.b. G

oing from 0-60 mph in 10 secc. Slamming on the brakes to come to a stop at a stop signd. Driving 60 miles per hour around a curve

1 answer:

Setler79 [48]3 years ago

6 0

C. Slamming on the brakes to come to a stop at a stop sign. Here you are Decelerating.

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What current is needed in the solenoid's wires?

marta [7]

Using Ampere's Law, the magnetic field produced inside this solenoid is given by
B = uo N I / h
where uo is the vacuum permeability, N is the number of turns in the solenoid and h is the length of the solenoid. Earth's magnetic field is around 50 microteslas in North America thus the current needed in the solenoid is
I = B h / (uo N) = (50 E-6 ) (4) / ((4 pi E-7)(6000) ) = 0.026 A
I = 26 mA
So you need a current of around 26 mA.

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2 years ago

System A has masses m and m separated by a distance r; system B has masses m and 2m separated by a distance 2r; system C has mas

Anna [14]

Answer:

System D --> System C --> System A --> System B

Explanation:

The gravitational force between two masses m1, m2 separated by a distance r is given by:

$F=G \frac{m_1 m_2}{r^2}$

where G is the gravitational constant. Let's apply this formula to each case now to calculate the relative force for each system:

System A has masses m and m separated by a distance r:

$F=G\frac{m \cdot m}{r^2}=G \frac{m^2}{r^2}$

system B has masses m and 2m separated by a distance 2r:

$F=G\frac{m \cdot 2m}{(2r)^2}=G \frac{2m^2}{4r^2}=\frac{1}{2} G \frac{m^2}{r^2}$

system C has masses 2m and 3m separated by a distance 2r:

$F=G\frac{2m \cdot 3m}{(2r)^2}=G \frac{6m^2}{4r^2}=\frac{3}{2} G \frac{m^2}{r^2}$

system D has masses 4m and 5m separated by a distance 3r:

$F=G\frac{4m \cdot 5m}{(3r)^2}=G \frac{20m^2}{9r^2}=\frac{20}{9} G \frac{m^2}{r^2}$

Now, by looking at the 4 different forces, we can rank them from the greatest to the smallest force, and we find:

System D --> System C --> System A --> System B

5 0

3 years ago

Hi, I need some science help ASAP. Here's the question:

ch4aika [34]

Answer:

Mass of the box is 25kg

Explanation:

From Newton's second law of motion

Force= mass. acceleration

With the symbol

F=m.a

m=F/a m=(50N)/(2m/s²)

m=25kg

7 0

3 years ago

A piston-cylinder device initially contains 1.4 kg saturated liquid water at 200oC. Now heat is transferred to the water until t

postnew [5]

Answer:

Explanation:

Given

mass of saturated liquid water $m=1.4\ kg$

at $200^{\circ}$ specific volume is $\nu =0.001157\ m^3\kg$ (From Table A-4,Saturated water Temperature table)

$V_1=m\nu _1$

$V_1=1.4\times 0.001157$

$V_1=1.6198\times 10^{-3}\ m^3$

Final Volume $V_2=4V_1$

$V_2=4\times (1.6198\times 10^{-3})$

$V_2=6.4792\times 10^{-3}\ m^3$

Specific volume at this stage

$\nu _2=\frac{V_2}{m}$

$\nu _2=\frac{6.4792\times 10^{-3}}{1.4}$

$\nu _2=0.004628\ m^3/kg$

Now we see the value and find the temperature it corresponds to specific volume at vapor stage in the table.

$T_2=T_1^{*}+\frac{T_2^{*}-T_1^{*}}{\alpha _2^{*}-\alpha _1^{*}}\times (\alpha _2-\alpha _1^{*})$

$T_2=370^{\circ}+\frac{373.95-370}{0.003106-0.004953}\times (0.004628-0.004953)$

$T_2=370.7^{\circ} C$

4 0

3 years ago

. A milk truck carries milk with density 64.6 lbyft3 in a horizontal cylindrical tank with diameter 6 ft. (a) Find the force exe

Goryan [66]

Answer:

Explanation:

one end of tank will be circular in shape . Area of circle A

= π r² , r is radius of the circle

= 3.14 x 3²

A = 28.26 ft³

To calculate force on the circular area , we first find pressure at the center of the circle which is at depth equal to r

pressure at the center = h d g ' here h = depth = r , d = density of milk

pressure = 3 x 64.6 x 32 poundal / ft²

= 6201.6 poundal / ft²

total force on circular face = pressure at the center x area of circle

= 6201.6 x 28.26

= 175257.21 poundal .

8 0

2 years ago