While competing in the Olympics, an athlete hurls a discus with a velocity of 15 m/s at an angle of 20. What is the horizontal c
2 answers:
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The car traverses a distance after time
according to
where is its acceleration, 10 m/s^2. The time it takes for the car to travel 25 m is
5 is pretty close to 4, so we can approximate the square root of 5 by 2. Then the car's velocity after 2 s of travel is given by
which makes C the most likely answer.
The question is incomplete. Here is the complete question.
Cars A nad B are racing each other along the same straight road in the following manner: Car A has a head start and is a distance beyond the starting line at t = 0. The starting line is at x = 0. Car A travels at a constant speed
. Car B starts at the starting line but has a better engine than Car A and thus Car B travels at a constant speed
, which is greater than
.
Part A: How long after Car B started the race will Car B catch up with Car A? Express the time in terms of given quantities.
Part B: How far from Car B's starting line will the cars be when Car B passes Car A? Express your answer in terms of known quantities.
Answer: Part A:
Part B:
Explanation: First, let's write an equation of motion for each car.
Both cars travels with constant speed. So, they are an uniform rectilinear motion and its position equation is of the form:
where
is initial position
v is velocity
t is time
Car A started the race at a distance. So at t = 0, initial position is .
The equation will be:
Car B started at the starting line. So, its equation is
Part A: When they meet, both car are at "the same position":
Car B meet with Car A after units of time.
Part B: With the meeting time, we can determine the position they will be:
Since Car B started at the starting line, the distance Car B will be when it passes Car A is units of distance.
Length of the pipe = 0.39 m
Third harmonic frequency = 1400 Hz
For the third harmonic:
Wavelength =
The center of the open pipe will host a node and the nearest anti - node from the center will be at the 0.25 × wavelength
Distance from center = 0.25 × wavelength
Distance =
Plugging the value of the length of the pipe (L) = 0.39 m = 39 cm
Distance =
Distance from the center to the nearest anti - node = 6.5 cm
Hence, the nearest distance to the anti - node from the center = 6.5 cm
So, option C is correct.