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chubhunter [2.5K]
3 years ago
7

What is Nucleosynthesis

Physics
2 answers:
BigorU [14]3 years ago
6 0
<span>the cosmic formation of atoms more complex than the hydrogen atom.</span>
Vaselesa [24]3 years ago
5 0
Formation of atoms more circuitous than hydrogen atom
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A projectile of mass 9.6 kg is launched from the ground with an initial velocity of 12.4 m/s at angle of 54° above the horizonta
Temka [501]

Answer:

The location is at (3.535, 1.162) m

Solution:

As per the question:

Mass of the projectile, m = 9.6 kg

Initial velocity, v = 12.4 m/s

Angle, \theta = 54^{\circ}

Mass of one fragment, m = 6.5 kg

Time taken by the fragment, t = 1.42 s

Height of the fragment, y = 5.9 m

Horizontal distance, x = 13.6 m

Now,

To determine the location of the second fragment:

Horizontal Range, R = \frac{v^{2}sin2\theta}{g}

R = \frac{12.4^{2}sin2(54)}{9.8} = 14.92\ m

Time of flight, t' = \frac{2vsin\theta}{g} = \frac{2\times 12.4sin108}{9.8}= 2.406\ s

Now, for the fragments:

Mass of the other fragment, m' = M - m = 9.6 - 6.5 = 3.1 kg

Distance traveled horizontally:

s_{x} = vcos\theta = 12.4cos54^{\circ}\times 1.42 = 10.35\ m

Distance traveled vertically:

s_{y} = vcos\theta - \frac{1}{2}gt^{2}

s_{y} = 12.4sin54^{\circ}\times 1.42 -  \frac{1}{2}\times 9.8\times 1.42^{2} = 14.25 - 9.88 = 4.37\ m

Now,

s_{x} = \frac{mx + m'x'}{M}

10.35= \frac{6.5\times 13.6 + 3.1x'}{9.6}

x' = 3.535 m

Similarly,

s_{y} = \frac{my + m'y'}{M}

4.37= \frac{6.5\times 5.9 + 3.1y'}{9.6} = 1.162\ m

The location of the other fragment is at (3.535, 1.162)

5 0
4 years ago
a person rearranging their living furniture expends 350 J of energy to push a coach 4.5 m across their living room calculate the
sergiy2304 [10]

1575 N

Explanation:

Step 1:

Let us consider that 350 J of energy is spent by that person to push a couch to 4.5 m from its initial position.

Let F be the force required and E be the energy spent and D be the distance traveled by the couch from its initial state.

In Physics, Work done  = Force / Displaced distance

Step 2:

Let the work done be 350 J and Distance be 4.5 m

Then Force exerted = 350*4.5 = 1575 N

5 0
3 years ago
A 2.0-m wire carrying a current of 0.60 A is oriented parallel to a uniform magnetic field of 0.50 T. What is the magnitude of t
konstantin123 [22]

Answer:

The force experienced  is 0.6 N

Explanation:

Given data

length of wire L= 2 m

current in wire I= 0.6 A

magnetic field B= 0.5

The force experienced can be represented as

F= BIL

F= 0.5*0.6*2\\\F= 0.6 N

7 0
3 years ago
The speed of sound in sea water is about 1530 m/s. If a sound wave has a frequency of 2.50 x 10^2 Hz, what is its wavelength in
Setler [38]

Answer: 6.12metres

Explanation:

The wavelength is the distance covered by the wave in one complete cycle. It is measured in metres, and represented by the symbol λ

Recall that Wavespeed (V) = Frequency F x wavelength λ

V = F λ

In this case,

Wavespeed of sound = 1530 m/s

Frequency of sound = 2.50 x 10^2 Hz

Wavelength = ? (let the unknown value be Z)

Apply V = F λ

1530 m/s = 2.50 x 10^2 Hz x Z

Z = (1530 m/s / 2.50 x 10^2 Hz)

Z = (1530 m/s / 250Hz)

Z = 6.12m

Thus, the wavelength of sound in sea water is 6.12m

5 0
4 years ago
Anyone who answer will get brainlest
Ganezh [65]

Answer:

D

Explanation:

work = Force x distance

work = 2000 x 2 = 4000

power = work÷ time

4000/.8 = 5000W

6 0
3 years ago
Read 2 more answers
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