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3 years ago

15

HBr + H₂SO₄ SO₂ + Br₂ + H₂O

2 answers:

mixer [17]3 years ago

8 0

Answer:

Oxidizing agent: +6

Reducing agent: -1

Explanation:

lisabon 2012 [21]3 years ago

3 0

The reaction equation is:
<span>HBr + H₂SO₄ </span>→ <span>SO₂ + Br₂ + H₂O

An oxidizing agent is a substance that itself becomes reduced and oxidizes the other chemical species in the reaction mixture. A reducing agent is similar, except that it becomes oxidized and reduces the other substance.
In the reaction, the valency of bromine changes from -1 to 0, so it is oxidized, making it the reducing agent. The valency of sulfur changes from +6 to +4, so it is reduced, making it the oxidizing agent.</span>

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Which of the following is not true about elements? 1. Elements are made of atoms of the same type. 2. Each element has a unique

Marat540 [252]

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<u>Elements can't be broken down</u>, into a simplre set of properties. They are one strict unit & cannot be broken down, however they can be added together to make a compound.

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2 years ago

The teacher said the volume of the liquid was 500 mL when measured a student found it was 499.7 mL what is the students percent

Natalka [10]

Answer:

<h2>0.06 % </h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

error = 500 - 499.7 = 0.3

actual volume = 500 mL

We have

$p(\%) = \frac{0.3}{500} \times 100 \\ = \frac{3}{50} \\$

We have the final answer as

<h3>0.06 % </h3>

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3 years ago

2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo

pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

<u>Chemical reaction involved</u>: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol) (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: $Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2$

<u>To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:</u>

$\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}$

$\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)$

$\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)$

<u>Therefore, the Gibb's free energy change at 37° C (310.15 K): </u><u>ΔG = (-2.45 kJ/mol)</u>

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3 years ago

If the gas in the piston above has a volume of 20.0 L at a temperature of 25 C what is the volume of that gas when it is heated

dexar [7]

Answer:

15.98 L

Explanation:

First, you need to find T1, T2, V1 and V2.

T1 = 25 C = 298.15 K (25C + 273.15K)

T2 = 100 C = 373.15 K (100C + 273.15K)

V1 = 20. L

V2 = ? (we are trying to find)

Next, rearrange to fit the formula

V2 = V1 x T1 / T2

Next, fill in with our numbers

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Do the math and you should get...

15.98 L

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Mashutka [201]

Explanation:

I can give you some examples;

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3)Soil

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3 years ago

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