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diamong [38]
4 years ago
5

How many grams of glucose would you need to make 500ml of an 8% solution?

Chemistry
2 answers:
julsineya [31]4 years ago
6 0
<span>) 8% solution means 8g/100 ml. So 500 ml= 40g. </span>
Archy [21]4 years ago
3 0

Answer:- 40 grams.

Solution:- We are asked to make 500 mL of 8% glucose solution. The percentage is the mass by volume percentage. 8% glucose solution means 8 grams of glucose present in 100 mL solution. From this given information, we can easily calculate the mass of glucose required to make 500 mL solution.

The calculations are shown as:

500mL(\frac{8g}{100mL})

= 40 g

So, 40 grams of glucose are required to make 500 mL of 8% solution.


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En el enlace covalente entre azufre y carbono (6 y 4 electrones en su ultima capa respectivamente) la molécula tendrá ?
d1i1m1o1n [39]

Answer:

a- Uno de carbono y dos de azufre

Explanation:

El compuesto formado entre el carbono y el azufre es CS2.

El carbono forma dos enlaces dobles con dos átomos de azufre.

Por lo tanto, el compuesto contiene un átomo de carbono y dos átomos de azufre.

6 0
3 years ago
When will diffusion slow down
scZoUnD [109]

Answer:

Exchange across cell membranes - diffusion. The higher the concentration gradient, the faster the rate of facilitated diffusion, up to a point. As equilibrium is reached the concentration gradient is much lower because the difference in concentrations is very small so the rate of facilitated diffusion will slow down and level off.

Explanation:

6 0
4 years ago
22.99 on the element sodium means the combined numbers of electrons and protons?
Anika [276]

Answer:

The answer is 11 electron and 11 protons respectively

Explanation:

Since the sodium is in it neutral state, number of electron is the same as the number of proton, which is 11.

8 0
3 years ago
Read 2 more answers
Classify each of the following as energy primarily transferred as HEAT or energy primarily transferred as WORK.
IgorLugansk [536]
number 1 is work number 2 is heat
6 0
3 years ago
For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, H_3PO_4 acid and there are three Ka values

K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}

The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

                             = 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

                             = 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

       = -log 6.2x10-8

       = 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

     = 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0
3 years ago
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