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3 years ago

What should a sailboat operator do when approaching a PWC head-on

Physics

1 answer:

nekit [7.7K]3 years ago

8 0

In accordance with the International Regulation for the prevention of collisions at sea:

1.- A sailing boat has a passing preference over a motorized boat, except when the motor boat is limited by its draft.

2.- The sailboat must maintain its course and speed.

3.- If it is evident that the PWC does not respond, the sailboat must sound the warning signal, and change its course to starboard.

4.- All actions must be taken as soon as possible.

5.- If a sailboat is using its engine, the situation changes, and in that case, both ships must alter to starboard.

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One Pro for supplements is the cost. True Or False

Nat2105 [25]

Answer:

False

Explanation:

8 0

3 years ago

A rock, with a density of 3.55 g/cm^3 and a volume of 470 cm^3, is thrown in a lake. a) What is the weight of the rock out of th

SIZIF [17.4K]

Answer:

a) Weight of the rock out of the water = 16.37 N

b) Buoyancy force = 4.61 N

c) Mass of the water displaced = 0.47 kg

d) Weight of rock under water = 11.76 N

Explanation:

a) Mass of the rock out of the water = Volume x Density

Volume = 470 cm³

Density = 3.55 g/cm³

Mass = 470 x 3.55 = 1668.5 g = 1.6685 kg

Weight of the rock out of the water = 1.6685 x 9.81 = 16.37 N

b) Buoyancy force = Volume x Density of liquid x Acceleration due to gravity.

Volume = 470 cm³

Density of liquid = 1 g/cm³

$\texttt{Buoyancy force}= \frac{470\times 1\times 9.81}{1000} = 4.61 N$

c) Mass of the water displaced = Volume of body x Density of liquid

Mass of the water displaced = 470 x 1 = 470 g = 0.47 kg

d) Weight of rock under water = Weight of the rock out of the water - Buoyancy force

Weight of rock under water = 16.37 - 4.61 =11.76 N

3 0

3 years ago

The length of second, s pendulum at a place where gravitational acceleration ]g] is 9.8 m/s

amm1812

O.99 m long .simple pendulum time period is 2s for second formula then use formula T=2pi.rt(lenght/gravity)

6 0

3 years ago

If eight water waves pass an ocean buoy each minute, and successive wave crests are 20 m apart, find the wave speed:____________

Llana [10]

Answer:

The wave speed is calculated below:

Explanation:

Given,

number of waves passed per minute = 8

time period = 1 minute = 60 s

distance between successive wave crests = 20 m

waves passing interval per second = $\frac{8}{60}$ $s^{-1}$

Now,

wave speed = 20 m × $\frac{8}{60}$ $s^{-1}$

= $\frac{8}3}$ m/s

= 2.67 m/s

Hence the wave speed is 2.67 m/s.

4 0

3 years ago

Total momentum before a collision is equal to total momentum after a collision.what does this define

otez555 [7]

Answer:haha

Explanation:dont know

3 0

3 years ago