Answer:
The hardness is more than 2.5. Hope this helps.
Answer:
Q = 30355.2 J
Explanation:
Given data:
Mass of ice = 120 g
Initial temperature = -5°C
Final temperature = 115°C
Energy required = ?
Solution:
Specific heat capacity of ice is = 2.108 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Q = m.c. ΔT
ΔT = T2 -T1
ΔT = 115 - (-5°C)
ΔT = 120 °C
Q = 120 g × 2.108 j/g.°C × 120 °C
Q = 30355.2 J
<u>Answer:</u> The energy of the complex is
<u>Explanation:</u>
To calculate the energy of the complex, we use the equation given by Planck which is:
where,
= Wavelength of the complex = (Conversion factor: )
h = Planck's constant =
c = speed of light =
= Avogadro's number =
= energy of the complex
Putting values in above equation, we get:
Conversion factor used: 1 kJ = 1000 J
Hence, the energy of the complex is
Answer: Option (c) is the correct answer.
Explanation:
Atomic number of sodium is 11 and its electronic configuration is . When sodium loses one electron then it will attain +1 charge and its electronic configuration will be as follows.
:
Atomic number of fluorine is 9 and its electronic configuration is . When fluorine gains an electron then it acquires -1 charge and its electronic configuration is as follows.
:
Atomic number of aluminium is 13 and its electronic configuration is . When aluminium loses its valence electrons then it acquires +3 charge and its electronic configuration is as follows.
:
Thus, we can conclude that the listing for aluminum is correct.