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3 years ago

How is oxygen purified?

2 answers:

8 0

Fractional distillation of liquid air. You need to be able to explain how nitrogen and oxygen are obtained from the air. You will recall that about 78% of the air is nitrogen and 21% is oxygen. These two gases can be separated by fractional distillation of liquid air

xxTIMURxx [149]3 years ago

3 0

Oxygen is obtained on a commercial scale through the liquefaction and distillation of ambient air at air separation plants. A secondpurification process may be necessary if ultra-high purity levels are required. High-purity oxygen can also be produced through the electrolysis of water.

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A string of length 0.6 M is vibrating at 100 Hz and its second harmonic and producing sound that moves at 340 m/s. What is true

Cloud [144]

Answer: the answer is B

Explanation: I just took the quiz :)

6 0

3 years ago

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We drive at a speed of 20 km/h for 3 hours. Then we drive 4 hours at 30 km/h. Calculate our average speed.

Afina-wow [57]

First speed = 20km/h

Time = 3 hours

Distance = 3×20

Second speed = 30km/h

Time = 4 hours

Distance = 4×30

Total distance = 60+120 = <u>180km</u>

Total time = 3+4 =<u> 7 hours</u>

Average speed = 180/7

Hope this will help...

4 0

3 years ago

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You will measure and record the time it takes the cart to travel certain distances, and then complete some calculations. In the

natka813 [3]

Answer:

Take the measurement of the distance (d) with a meter rule (in meters) and also measure the time (t) of the travel in seconds with a stopwatch.

question: What is the speed of the cart?

Explanation:

The speed of an object in motion is the distance covered by the object with respect to time, that is, the ratio of distance covered to the time taken to reach that distance.

Speed = distance / time

= d (in meters m) / t (in seconds s) = m/s

6 0

3 years ago

An adiabatic nozzle has an inlet area of 1 m^2 and an outlet area of 0.25 m^2. Water enters the nozzle at a rate of 5 m^3/s and

svlad2 [7]

Answer:

v=20m/S

p=-37.5kPa

Explanation:

Hello! This exercise should be resolved in the next two steps

1. Using the continuity equation that indicates that the flow entering the nozzle must be the same as the output, remember that the flow equation consists in multiplying the area by the speed

Q=VA

for he exitt

Q=flow=5m^3/s

A=area=0.25m^2

V=Speed

solving for V

$V=\frac{Q}{A} \\V=\frac{5}{0.25} =20m/s$

velocity at the exit=20m/s

for entry

$V=\frac{5}{1} =5m/s$

To find the pressure we use the Bernoulli equation that states that the flow energy is conserved.

$\frac{P1}{\alpha } +\frac{v1^2}{2g} =\frac{P2} {\alpha } +\frac{v2^2}{2g}$

where

P=presure

α=9.810KN/m^3 specific weight for water

V=speed

g=gravity

solving for P1

$(\frac{p1}{\alpha } +\frac{V1^2-V2^2}{2g})\alpha =p2\\(\frac{150}{9.81 } +\frac{5^2-20^2}{2(9.81)})9.81 =p2\\P2=-37.5kPa$

the pressure at exit is -37.5kPa

7 0

3 years ago

A temperature of 200 degrees F is equivalent to approximately

Ann [662]

(1) Changing Fahrenheit to Celsius:
The formula used to convert from Fahrenheit to Celsius is as follows:
C = <span>(F - 32) * 5/9
</span>We are given that F=200, substitute in the above formula to get the corresponding temperature in Celsius as follows:
C = (200-32) * (5/9) = 93.333334 degrees Celsius

(2) Changing the Fahrenheit to kelvin:
The formula used to convert from Fahrenheit to kelvin is as follows:
K = <span>(F - 32) * 5/9 + 273.15
</span>We are given that F = 200. substitute in the above formula to get the corresponding temperature in kelvin as follows:
K = (200-32)*(5/9) + 273.15 = 366.483334 degrees kelvin

5 0

3 years ago

Read 2 more answers