The weight of an object at the surface of a planet is given by:
where m is the mass and g is the gravitational acceleration, given by
where G is the gravitational constant, M is the planet's mass, and r the radius of the planet.
At Earth's surface,
. Since we know the weight of the person at Earth's surface, F=670 N, we can find his mass:
Now we have to calculate the value of g at the surface of the neutron star. The mass of the neutron star is 25 times the Sun's mass:
While its radius is:
Therefore, the value of g at the neutron star surface is
Therefore, the weight of the person at the surface of the neutron star would be
The velocity (V) of a wave is the frequency (F) times the wave length (lambda):
V = F * lamda
lambda is the distance from crest to crest which is twice the distance from crest to trough.
=> lamba = 2 * 3.00 m = 6.00 m
F = number of waves / time = 13.0 waves / 20.2 s
Now you can plug in the values in the formula of V:
V = 6.00 m/wave* 13.0 waves / 20.2 s = 3.86 m/s
Answer: 3.86 m/s
Answer:
Acceleration: (final velocity - starting velocity) / (time)
Acceleration: (30-12)/15
Acceleration: 18/15
Acceleration: 6/5 m/s^2
Let me know if this helps!
Answer:
cryosphere is all those areas of earth where the surface is frozen while hydrosphere is all waters of earth, as distinguished from the land and the gasses of the atmosphere
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