Answer:
the extension recorded by the student would be smaller than the actual extension of the spring
I think this is correct, but I am not entirely certain.
Find the force constant of the spring:
F = - KX
(0 - 62.4) = -K(0.172m)
-362.791 = -K
362.791 N/m = K
Find the work done in stretching the spring:
W = (1/2)KX
W = (1/2)(362.791)(0.172m)
W = 31.2 J
I think its true because they are a soft solid that can be broken down into a liquid... Hope this helps in any way :3
Normal force, friction force, gravitational force
