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Mnenie [13.5K]
4 years ago
12

Your engineering firm has been hired as a consultant to evaluate engineered channels to replace an existing natural stream. The

existing channel has a length of 1.2 miles with an average bedslope of0.0042ft/ft. Thedesign flowfor this channel is2,250 cfs.The client requests that you conduct a feasibility study to replace the natural stream with a concrete-linedchannel. Base your design on the best hydraulic section and select two of the following section shapes to evaluate:rectangular, trapezoidal, triangular, and half-circularsections.Provide a freeboard of at least 10% of the flow depthat design discharge. Subcritical flowis preferredin the engineered channel. After completing the design of the channel, perform an extreme event analysis by determining the normal depth for a flow of twice the design flow. Discuss ifflooding is an issue for this extreme event.

Engineering
1 answer:
garik1379 [7]4 years ago
6 0

Answer:

Check the explanation

Explanation:

DEPTH:-- the distance from the top or surface to the bottom of something.

Kindly check the attached images below to see the step by step explanation to the question above.

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The high-pressure fuel pumps used in gasoline direct-injection (GDI) systems are powered by ________.
lidiya [134]

Answer:

Camshaft

Explanation:

5 0
2 years ago
A road has a crest curve, where the PVI station is a 71 35. The road transitions from a 2.1% grade to a -3.4% grade. The highest
sveticcg [70]

Answer:

Stat PVC = Stat(82+98.5)

Stat PVT = Stat(59+71.5)

Explanation

PVI = 71 + 35

Let G1 = Grade 1; G2 = Grade 2

G1 = +2.1% ; G2 = -3.4%

Highest point of curve at station = 74 + 10

General equation of a curve:

y = ax^{2} +bx+c\\dy/dx=2ax+b\\

At highest point of the curve dy/dx=o

2ax+b=0\\x=-b/2a\\x=G1L/(G2-G1)\\x=L/2 +(stat 74+10)-(stat 71+35)\\x=L/2 + 275

-G1L/(G2-G1) = (L/2 + 275)/100\\L = -2327 ft\\Station PVC = Stat(71+35)+(-2327/2)\\\\Stat PVC = 7135-1163.5\\Stat PVC = Stat(82+98.5)\\

Station PVT

Station PVT = Stat PVI + (L/2)\\Station PVT = Stat(71+35)+(-2327/2)\\Station PVT = 7135-1163.5\\Stat PVT = Stat(59+71.5)

3 0
3 years ago
Telnet into a Web server and send a multiline request message. Include in the request message the If-modified-since: header line
KiRa [710]

Answer:

The following command is issued

in Windows command prompt

followed by the HTTP GET

message to the “utopia.poly.edu"

web server:

> telnet utopia.poly.edu 80

As the index.html page in the web

server was not modified since

Mon, 18 May 2015 09:23:34GMT,

the following outputwas displayed

when the above commands were

issued on Sat, 23 May 2015.

The first 4 lines are the GET

message and header lines input by

the user.

The next 4 lines (starting from

HTTP/1.1 304 Not Modified) are

the response from the web server.

Explanation:

File is also attach which might help to explain the answer.

5 0
3 years ago
I will mark as brainliest !
Sliva [168]

Answer:

7.8 Mph

Explanation:

Rate of cycling = 1.1 rev/s

Rear wheel diameter = 26 inches

Diameter of sprocket on pedal = 6 inches

Diameter of sprocket on rear wheel = 4 inches

Circumference of rear wheel =  \pi d=26\piπd=26π

Speed would be

\begin{gathered}\text{Rate of cycling}\times \frac{\text{Diameter of sprocket on pedal}}{\text{Diameter of sprocket on rear wheel}}\times{\text{Circumference of rear wheel}}\\ =1.1\times \frac{6}{4}\times 26\pi\\ =134.77432\ inches/s\end{gathered}Rate of cycling×Diameter of sprocket on rear wheelDiameter of sprocket on pedal×Circumference of rear wheel=1.1×46×26π=134.77432 inches/s

Converting to mph

1\ inch/s=\frac{1}{63360}\times 3600\ mph1 inch/s=633601×3600 mph

134.77432\ inches/s=134.77432\times \frac{1}{63360}\times 3600\ mph=7.65763\ mph134.77432 inches/s=134.77432×633601×3600 mph=7.65763 mph

The Speed of the bicycle is 7.8 mph

3 0
3 years ago
insulated rigid tank 3kg saturated liquid vapor at 200kpa. 3/4 mass is liquid. heated until all is vaporized. determine quality
n200080 [17]

Answer:

from the steam table

we get to know the values

p_{1} =200Kpa\\x_{1} =0.25

therefore\\v_{i} =v_{f} +x_{1} v_{fg} \\v_{i} =0.001061+(0.25)(0.88578-0.001061)\\v_{i} =0.22224m^3/kg

we have

s_{i} =s_{f} +x_{1} s_{fg} \\s_{i} =1.5302+(0.250)(5.5968)=2.9294 Kj/kg.K

to find s 2

v_{2} =v_{1} =0.22224m^3/kg\\x_{2} =1\\s_{2} =6.6335Kj/kg.K\\

so the entropy change is

S=m(s_{2}- s_{1} )

put values

S=(3kg)(6.6335-2.9294)Kj/kg.K\\S=11.1123Kj/K

6 0
3 years ago
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