Compound X has the formula C8H14. X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form
a mixture of cis- and trans-1-ethyl-3-methylcyclopentane. Treatment of X with ozone followed by zinc in aqueous acid gives a ketone and formaldehyde (CH2=O). What is the structure of X?
1 answer:
Answer:
1-Ethyl-3-methylidenecyclopentane
Step-by-step explanation:
Formula = C₈H₁₄. An alkane has formula C₈H₁₈. ∴ X contains 2 double bonds, 2 rings, or 1 ring and 1 double bond.
X absorbs only 1 mol of hydrogen. ∴ X contains 1 ring and 1 double bond.
Hydrogenation gives 1-ethyl-3-methylcyclopentane.
Ozonolysis gives formaldehyde, so X must contain a =CH₂ group.
Hydrogenation of X converted the =CH₂ to -CH₃.
X is 1-ethyl-3-methylidenecyclopentane.
You can see the reactions in the image below.
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We can solve this problem by using Henry's law.
Henry's law states that the amount of dissolved gas is proportional to its partial pressure.
C is <span>the solubility of a gas.
</span><span>k is Henry's law constant.
</span><span>P is the partial pressure of the gas.
</span>We can calculate the constant from the first piece of information and then use Henry's law to calculate solubility in open drink.
0.12=4k
k=0.03
Now we can calculate the solubility in open drink.
Now we need to convert it to g/L. One mol of CO2 is 44.01<span>g.
</span>The final answer is:
Henry's law states that the amount of dissolved gas is proportional to its partial pressure.
C is <span>the solubility of a gas.
</span><span>k is Henry's law constant.
</span><span>P is the partial pressure of the gas.
</span>We can calculate the constant from the first piece of information and then use Henry's law to calculate solubility in open drink.
0.12=4k
k=0.03
Now we can calculate the solubility in open drink.
Now we need to convert it to g/L. One mol of CO2 is 44.01<span>g.
</span>The final answer is:
Explanation:
As it is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity =
As it is given that molarity is 0.10 M and volume is 10.0 ml. As 1 ml equals 0.001 L. Therefore, 10.0 ml will also be equal to 0.01 L.
Hence, putting these values into the above formula as follows.
Molarity =
0.10 M =
no. of moles = 0.001 mol
As molar mass of KCN is equal to 65.12 g/mol. Therefore, calculate the mass of KCN as follows.
No. of moles =
0.001 mol =
mass = 0.06152 g
Thus, we can conclude that 0.06152 grams of KCN are in 10.0 ml of a 0.10 M solution.