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2 years ago

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If a cart of 4 kg mass has a force of 8 newtons exerted on it, what is its acceleration?

2 answers:

dybincka [34]2 years ago

6 0

M = 4kg
F =8N
a..?

F =m.a
8 = 4.a
a = 2m/s^2

Anastaziya [24]2 years ago

5 0

Answer:

a=2m/s^2

Explanation:

If a cart of 4 kg mass has a force of 8 newtons exerted on it, what is its acceleration

first foremost, we define basic terms

Mass=is the quantity of matter in a body ,kg

Acceleration= change in velocity per time(m/s^2)

Force= Is that which tends to change a body's state of rest or uniform motion in a straight line.

It is also the pull or push on a body.

From newton's second law of motion which states that rate of change in momentum is proportional to the force applied. Where k=1

Fαm(v/t)

F=km(v/t)

K=1

f=ma

Since v/t= acceleration

velocity/time=accel

8=4a

a=8/4

a=2m/s^2

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A car is moving at 19 m/s along a curve on a horizontal plane with radius of curvature 49m.

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$\mu =0.75$

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<u>Frictional Force </u>

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$F_c=m.a_c$

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$\displaystyle a_c=\frac{v^2}{r}$

Where v is the tangent speed of the car and r is the radius of curvature. Replacing the formula into the first one

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For the car to keep on the track, the friction must have the exact same value of the centripetal force and balance the forces. The friction force is computed as

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