Answer:
preservation of raw materials
Explanation:
Reusing and recycling is the process by which the used products are used again or recycled in different form to use it again. Excessive use of the raw materials can lead to their extinction. Recycling the materials helps in decreasing the pollution in the environment. It also helps in reduction in the emission of the harmful gases. When municipal wastes are reused or recycled, the raw materials are preserved. These are the process involved in sustainable use of resources.
The 3-dimensional orientation of a sublevel is known as atomic orbital.
In quantum mechanics, Atomic orbitals are locations around an atom's nucleus where electrons are most likely to be at any particular time(specific orbits). These specific orbits exist in levels and can be broken down into sublevels.
Each sublevel has an orbital and it is oriented differently in 3-dimensional space.
The atomic orbital is a mathematical function that depicts how one or two electrons in an atom behave as seen in waves.
Learn more about atomic orbitals here:
brainly.com/question/1832385
Answer:
1.12g/mol
Explanation:
The freezing point depression of a solvent for the addition of a solute follows the equation:
ΔT = Kf*m*i
<em>Where ΔT is change in temperature (Benzonitrile freezing point: -12.82°C; Freezing point solution: 13.4°C)</em>
<em>ΔT = 13.4°C - (-12.82) = 26.22°C</em>
<em>m is molality of the solution</em>
<em>Kf is freezing point depression constant of benzonitrile (5.35°Ckgmol⁻¹)</em>
<em>And i is Van't Hoff factor (1 for all solutes in benzonitrile)</em>
Replacing:
26.22°C = 5.35°Ckgmol⁻¹*m*1
4.90mol/kg = molality of the compound X
As the mass of the solvent is 100g = 0.100kg:
4.9mol/kg * 0.100kg = 0.490moles
There are 0.490 moles of X in 551mg = 0.551g, the molar mass (Ratio of grams and moles) is:
0.551g / 0.490mol
= 1.12g/mol
<em>This result has no sense but is the result by using the freezing point of the solution = 13.4°C. Has more sense a value of -13.4°C.</em>
Catod(-)
K⁺
2H20 +2e⁻ ---> H2 +2OH⁻
We can also say, that
K⁺ +OH⁻ +H2 = KOH +H2
At the cathode KOH and H2 are formed.
