Question

The specific heat of a certain type of cooking oil is 1.75 J / ( g ⋅ ° C ) . 1.75 J/(g⋅°C). How much heat energy is needed to raise the temperature of 2.87 kg 2.87 kg of this oil from 23 ° C 23 °C to 191 ° C?

Answer 1

Answer:

Q =843780 J

Explanation:

Given that,

The specific heat of a certain type of cooking oil is, $c=1.75\ J/g^{\circ}C$

Mass of the oil, m = 2.87 kg = 2870 g

Initial temperature, $T_i=23^{\circ}C$

Final temperature, $T_f=191^{\circ}C$

To find,

Heat energy needed to raise the temperature.

Solution,

The heat energy needed to raise the temperature in terms of specific heat is given by :

$Q=mc(T_f-T_i)$

$Q=2870\ g\times 1.75\ J/g^{\circ}C\times (191^{\circ}C-23^{\circ}C)$

$Q=843780\ J$

So, the heat energy needed to raise the temperature is 843780 J.