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hodyreva [135]
3 years ago
13

A car traveling 90 km/hr is 100 m behind a truck traveling 50 km/hr. How long will it take the car to reach the truck?

Physics
2 answers:
Ber [7]3 years ago
8 0

v = speed of car = 90 km/h

u = speed of truck = 50 km/h

d = initial separation distance = 100 m = 0.1 km

They meet at time t such that

vt = d + ut

t(v - u) = d

t = d/(v - u) = (0.1 km) / [(90 - 50) km/h] = 0.0025 hours

olganol [36]3 years ago
7 0

95t - .210 = 50t

95t - 50t = 0.210

45t = 0.210

t = 0.210/45

t = 0.0047 km/hr

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At the beginning, when the ball is thrown from the ground, it has only kinetic energy, which is given by

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As the ball goes up, its speed decreases, so its kinetic energy decreases and converts into gravitational potential energy. When the ball reaches its maximum height, the speed has become zero, and all the kinetic energy has been converted into gravitational potential energy, given by:

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And we can solve the equation to find v, the initial speed of the ball:

v=\sqrt{2gh}=\sqrt{2(9.8 m/s^2)(10 m)}=14 m/s


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