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Alex777 [14]
2 years ago
12

1. If 22.5 L of nitrogen at 1.25 atm are compressed to 2.10 atm at constant temperature. What is the new

Chemistry
1 answer:
Lemur [1.5K]2 years ago
3 0

Answer:

V₂ = 13.4 L

Explanation:

Given data:

Initial volume of gas = 22.5 L

Initial pressure = 1.25 atm

Final pressure = 2.10 atm

Final volume = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

<em>Mathematical expression: </em>

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.25 atm × 22.5 L = 2.10 atm × V₂

V₂ = 28.125 atm. L/ 2.10 atm

V₂ = 13.4 L

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Answers and Explanation:

a)- The chemical equation for the corresponden equilibrium of Ka1 is:

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Because Ka1 correspond to a dissociation equilibrium. Nitrous acid (HNO₂) losses a proton (H⁺) and gives the monovalent anion NO₂⁻.

b)- The relation between Ka and the free energy change (ΔG) is given by the following equation:

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At the equilibrium: ΔG=0 and Q= Ka. So, we can calculate ΔGº by introducing the value of Ka:

⇒ 0 = ΔGº + RT ln Ka

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  ΔGº= 19092.8 J/mol

c)- According to the previous demonstation, at equilibrium ΔG= 0.

d)- In a non-equilibrium condition, we have Q which is calculated with the concentrations of products and reactions in a non equilibrium state:

ΔG= ΔGº + RT ln Q

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ΔG= ΔGº + RT ln Q

ΔG= 19092.8 J/mol + (8.314 J/K.mol x 298 K x ln (1.88 10⁻⁴)

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NADH + H⁺ + FMN + Q ⟶ NAD⁺ + FMN + QH₂

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