PH is based on a logarithmic scale, so every number is 10 times that of the one under it. For instance, say 8 has 10 OH-. This means that 11 should have 10000 OH-.
It has 10^3 times the amount of OH ions.
(0.22)*(159.3) + (0.78)*(161.2)
34.046 + 125.736 = 159.8 g/mole
A cold front is the leading edge of a cooler mass of air, replacing at ground level a warmer mass of air, which lies within a fairly sharp surface trough of low pressure.
Answer:
THE AMOUNT OF HEAT ABSORBED DURING THE REACTION IS 151.64 JOULES
Explanation:
Mass = 12.58 g
Specific heat of CaCO3 = 0.82 J/g K
Change in temperature = 38.3 C - 23.6 C = 14.7 C
How many joules of heat are absorbed?
Heat of a reaction is the amount of heat absorbed or evolved when a gram of a sample is raised by 1 C.
Heat = mass * specific heat * change in temperature
Heat = 12.58 * 0.82 * 14.7
Heat = 151.64 J
The amount of joules absorbed during this reaction is 151.64 J.
Answer: (a) K *[A][B]^2
(b) The answer is B
Explanation:
A)
Step1:A+B<--> C (fast)
Step2: B+C→D(slow)
Rate depends on slowest step.
so,
rate = k' [B][C] ...eqn 1
But C is intermediate.so use step 1
Since 1st step is an equilibrium,
Kc = [C] /[A][B]
so,
[C] = Kc [A][B] ...eqn 2
put eqn 2 in eqn 1
rate = k' *[B] * Kc [A][B]
= k'Kc*[A][B]^2
= K *[A][B]^2 {writing k'Kc = K}
Answer: K *[A][B]^2
B)
Answer is B
Since rate depends on slowest step.
if slowest step is:
X2Y2+Z2→X2Y2Z+Z
then only,
rate= k[X2Y2][Z2]
Answer: B