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Sergio039 [100]
2 years ago
12

a student adds 3.5 moles of solute to enough water to make a 1500mL solution. what is the concentration?

Chemistry
2 answers:
hichkok12 [17]2 years ago
8 0

Hey there!:

Molarity, molar concentration, concentration in mol/L or concentration in quantity of matter is the ratio of the amount of matter of the solute (mol) by the solution volume (in liters), expressed in the Unit mol/L (molar).

Number of moles  = 3.5 moles

1 L = 1000 mL

Volume in liters  = 1500 mL / 1000 =>  1.5 L

Therefore:

Molarity = number of moles / Volume in liters:

Molarity = 3.5 / 1.5

Molarity =  2.333 M

Hope this helps!

aksik [14]2 years ago
7 0
<h2>Hello!</h2>

The answer is:

MolarConcentration=\frac{3.5moles}{volume(1.5L)}=2.33molar

<h2>Why?</h2>

Since there is not information about the solute but only its mass, we need to assume that we are calculating the molar concentration of a solution or molarity. So, need to use the following formula:

MolarConcentration=\frac{mass(solute)}{volume(solution)}

Now, we know that the mass of the solute is equal  3.5 moles and the volume is equal to 1500 mL or 1.5L

Then, substituting into the equation, we have:

MolarConcentration=\frac{3.5moles}{1.5L}=2.33molar

Have a nice day!

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Answer:

- Both accurate and precise.

Explanation:

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Answer:

\large \boxed{\text{528.7 g} }

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It often helps to write the heat as if it were a reactant or a product in the thermochemical equation.

Then you can consider it to be 11018 "moles" of "kJ"  

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r:                      32.00

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\text{Moles of O}_{2} = \text{7280 kJ} \times \dfrac{\text{25 mol O}_{2}}{\text{11 018 kJ}} = \text{16.52 mol O}_{2}

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\text{Mass of C$_{8}$H}_{18} = \text{16.52 mol O}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol O}_{2}} = \textbf{528.6 g O}_{2}\\\text{The reaction requires $\large \boxed{\textbf{528.67 g O}_{2}}$}

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Answer:

QP

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Q donates 1 electron,

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