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3 years ago

Which is the next logical step in balancing the given equation? CS2(l) + Cl2(g) CCl4(l) + S2Cl2(l)

Chemistry

2 answers:

denis23 [38]3 years ago

5 0

Answer:

CS₂(l) + 3Cl₂(g) → CCl₄(l) + S₂Cl₂(l)

Explanation:

The next logical step is to list the number of C, Cl, and S atoms on the reactant and product side of the equation.

CS₂(l) + Cl₂(g) → CCl₄(l) + S₂Cl₂(l)

There is 1 C atom on both the reactant and product side of the equation.

There are two 2 S atoms on both the reactant and product side of the equation.

There are 2 Cl atoms on the reactant side and 6 (4+2) Cl atoms on the product side. Therefore to balance the equation we have to place a 3 coefficient before Cl₂ on the reactant side of the equation.

Therefore the final balanced equation is,

CS₂(l) + 3Cl₂(g) → CCl₄(l) + S₂Cl₂(l)

sasho [114]3 years ago

4 0

CS2(l)+Cl2(g)=CCl4(l)+S2Cl2(l)
1 C atom gets in , 1 C atom gets out
2 S atoms get in , 2 S atoms get out
2Cl atoms get in , 6 Cl atoms get out => we have to put a 3 in front of Cl2

Balanced equation:
CS2(l)+3Cl2(g)=CCl4(l)+S2Cl2(l)

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3 years ago

Copper(II) sulfide is formed when copper and sulfur are heated together. In this reaction,

storchak [24]

Answer:

The mass of copper(II) sulfide formed is:

= 81.24 g

Explanation:

The Balanced chemical equation for this reaction is :

$Cu(s) + S\rightarrow CuS$

given mass= 54 g

Molar mass of Cu = 63.55 g/mol

$Moles = \frac{given\ mass}{Molar\ mass}$

$moles=\frac{54}{63.55}$

Moles of Cu = 0.8497 mol

Given mass = 42 g

Molar mass of S = 32.06 g/mol

$Moles = \frac{given\ mass}{Molar\ mass}$

$moles=\frac{42}{32.06}$

Moles of S = 1.31 mol

Limiting Reagent : The reagent which is present in less amount and consumed in a reaction

First find the limiting reagent :

$Cu + S\rightarrow CuS$

1 mol of Cu require = 1 mol of S

0.8497 mol of Cu should require = 1 x 0.8497 mol

= 0.8497 mol of S

S present in the reaction Medium = 1.31 mol

S Required = 0.8497 mol

S is present in excess and Cu is limiting reagent

All Cu is consumed in the reaction

Amount Cu will decide the amount of CuS formed

$Cu + S\rightarrow CuS$

1 mole of Cu gives = 1 mole of Copper sulfide

0.8497 mol of Cu = 1 x 0.8497 mole of Copper sulfide

= 0.8497

Molar mass of CuS = 95.611 g/mol

$Moles = \frac{given\ mass}{Molar\ mass}$

$0.8497 = \frac{given\ mass}{95.611}$

Mass of CuS = 0.8497 x 95.611

= 81.24 g

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