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Nataly_w [17]
3 years ago
11

A car is driving down the road at 30 MPH. A bug hits the windshield with a force of 50N. With what force does the car hit the bu

g?
Group of answer choices

80N

20N

50N

300N
Physics
2 answers:
sp2606 [1]3 years ago
7 0
80N the answer of that question
Feliz [49]3 years ago
5 0

Answer:

80 N

Explanation:

The windshield is a part of the car and the bug hits it so the bug hits the car. they both are in opposite directions so their total force will be 80N

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The acceleration due to gravity on the moon is 1. 6 m/s2, about a sixth that of Earth’s. Which accurately describes the weight o
snow_tiger [21]

Weight is the force applied on the planet by its mass. The weight of an object is 6 times lighter than that of the earth. Option C is correct.

What is Wight?

  • It is the product of the mass and the gravitational acceleration.
  • Weight is the force applied on the planet by its mass.

The formula of weight is,

w = mg

Where,

w- weight

m - mass

g- gravitational acceleration

In the question given here the gravitational acceleration of the moon is 6 times less than that of the earth.

Therefore, the weight of an object is 6 times lighter than that of the earth.

Learn more about gravitational acceleration:

brainly.com/question/10888182

4 0
3 years ago
Net force of 200 newtons is applied to a wagon for 3 seconds
AveGali [126]

Momentum of the wagon increases by (200 x 3)

                                                     = 600 newton-sec

                                                     = 600 kg-m/sec
 
6 0
4 years ago
Two charged objects, A and B, are exerting an electric force on each other. What will happen if the charge on A is increased?
ozzi

Answer: The forces acting on both of them will increase in magnitude.

Explanation:

According to Coulomb's law, the electrostatic force between two bodies is proportional to the product of their two charges. If the charge on A is increased this product increases in size (it must have been non-zero to begin with, since there was a force between them at first). Thus, the force between them rises.

6 0
3 years ago
Simplify 45÷3+2×8-12+42​
Rufina [12.5K]

Answer:

Explanation is in the picture and the answer is 16

4 0
4 years ago
2) A traffic light of weight 100 N is supported by two ropes as shown. Let T1 and T2 are the tensions.
GarryVolchara [31]

Hi there!

a.

We know that:

\Sigma F_y = 0 \\\\\Sigma F_x = 0

Begin by determining the forces in the vertical direction:

W = weight of traffic light

T₁sinθ = vertical component of T₁

T₂sinθ = vertical component of T₂

b.

The ropes provide a horizontal force:

T₁cosθ = Horizontal component of T1

T₂cosθ = Horizontal component of T2

Thus:

0 = T₁cosθ  - T₂cosθ

T₁cosθ = T₂cosθ

T₁ = T₂

c.

Since the angles for both ropes are the same, we can say that:

T₁ = T₂

Sum the forces:

ΣFy = T₁sinθ + T₁sinθ - W = 0

2T₁sinθ = W

d.

Now, we can begin by solving for the tensions:

2T₁sinθ = W

T_1 = T_2 =  \frac{W}{2sin\theta} = \frac{100}{2sin(37)} = \boxed{83.08 N}

8 0
3 years ago
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