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Anika [276]
3 years ago
14

Explain the Impulse-Momentum Theorem.

Physics
1 answer:
Inessa05 [86]3 years ago
4 0

The impulse-theorem states that the change in momentum of an object is equal to the impulse exerted on it

Explanation:

The impulse-theorem states that the change in momentum of an object is equal to the impulse exerted on it.

Mathematically, we have:

- The impulse is defined as the product between the force exerted (F) and the duration of the collision (\Delta t):

I=F \Delta t

- The change in momentum is equal to the product between the mass of the object (m) and the change in velocity (\Delta v):

\Delta p = m \Delta v

So, the theorem can be written as

F\Delta t = m \Delta v

This theorem can be proved by using Newton's second law. In fact, we know that

F=ma (1)

where a is the acceleration of the object. However, we can re-write the acceleration as the rate of change of velocity:

a=\frac{\Delta v}{\Delta t}

Therefore, (1) becomes:

F=m\frac{\Delta v}{\Delta t}

And by re-arranging,

F\Delta t = m \Delta v

Which is exactly the formula of the impulse theorem.

Learn more about impulse and momentum:

brainly.com/question/9484203

#LearnwithBrainly

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The density of gasoline is 730 kg/m3 at 0°C. Its average coefficient of volume expansion is 9.60 10-4(°C)−1. Assume 1.00 gal of
kipiarov [429]

Answer: 0.4911 kg

Explanation:

We have the following data:

\rho_{0\°C}= 730 kg/m^{3} is the density of gasoline at 0\°C

\beta=9.60(10)^{-4} \°C^{-1} is the average coefficient of volume expansion

We need to find the extra kilograms of gasoline.

So, firstly we need to transform the volume of gasoline from gallons to m^{3}:

V=8.50 gal \frac{0.00380 m^{3}}{1 gal}=0.0323 m^{3} (1)

Knowing density is given by: \rho=\frac{m}{V}, we can find the mass m_{1} of 8.50 gallons:

m_{1}=\rho_{0\°C}V

m_{1}=(730 kg/m^{3})(0.0323 m^{3})=23.579 kg (2)

Now, we have to calculate the factor f by which the volume of gasoline is increased with the temperature, which is given by:

f=(1+\beta(T_{f}-T_{o})) (3)

Where T_{o}=0\°C is the initial temperature and T_{f}=21.7\°C is the final temperature.

f=(1+9.60(10)^{-4} \°C^{-1}(21.7\°C-0\°C)) (4)

f=1.020832 (5)

With this, we can calculate the density of gasoline at 21.7\°C:

\rho_{21.7\°C}=730 kg/m^{3} f=(730 kg/m^{3})(1.020832)

\rho_{21.7\°C}=745.207 kg/m^{3} (6)

Now we can calculate the mass of gasoline at this temperature:

m_{2}=\rho_{21.7\°C}V (7)

m_{2}=(745.207 kg/m^{3})(0.0323 m^{3}) (8)

m_{2}=24.070 kg (9)

And finally calculate the mass difference \Delta m:

\Delta m=m_{2}-m_{1}=24.070 kg-23.579 kg (10)

\Delta m=0.4911 kg (11) This is the extra mass of gasoline

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4 years ago
The convection zone is the outer most layer of the suns blank hot gases rise and then blank hear the loops form by singing cool
lora16 [44]

Answer:

Explanation:

The sun is made up of 6 parts. Namely:

  1. The core
  2. The radiation zone
  3. The convection zone
  4. The photosphere
  5. The chromosphere and
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The convection area is just above the radiation zone. As materials from the suns core are heated, they rise above the radiation zone towards the EDGE of the convection area then sinks back again into the radiative zone for more heat.

The radiative zone is 12.6 million Fahrenheit hot and is just above the core.

The core of the son is not solid but plasma whose motion is like gas. Its temperature stands at 48 million Fahrenheit

Cheers

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3 years ago
Evaluate A car company wants to build a wind-powered car that converts 100 percent of the mechanical energy in the wind to the m
lorasvet [3.4K]

Answer:

There's one or two reasons, depending on what is meant by "wind-powered car".

The first reason is that it's impossible for any transfer of energy to be 100% efficient.  There will always be frictional losses.

Secondly, if the company means that they want to attach a wind turbine to the car so that the car is powered by the same wind that it generates, that violates the conservation of energy.

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nordsb [41]

Answer:

m = 1 kg

Explanation:

Given that,

The force constant of the spring, k = 39.5 N/m

The frequency of oscillation, f = 1 Hz

The frequency of oscillation is given by the formula as formula as follows :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}} \\\\f^2=\dfrac{k}{4m\pi^2}\\\\m=\dfrac{k}{4\pi^2 f^2}\\\\m=\dfrac{39.5}{4\pi^2 \times (1)^2}\\\\m=1\ kg

So, the mass that is attached to the spring is 1 kg.

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What is the definition of Cubit
disa [49]

Answer:

See below.

Explanation:

Cubit is a unit of length based on the length of the forearm from the elbow to the tip of the middle finger and usually equal to about 18 inches (46 centimeters).

It is an ancient unit of length used in ancient Egypt and is also known as "ancient Egyptian royal cubit."

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