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8_murik_8 [283]
3 years ago
13

What is the total displacement???

Physics
2 answers:
Karo-lina-s [1.5K]3 years ago
6 0

Answer: 562.5 m

Displacement = velocity \times time= area under the curve in velocity-time graph

The area of the quadrilateral formed by the graph is given by:

A=\frac{(a+b)}{2} h

where, a and b are two parallel sides of the quadrilateral, h is the perpendicular distance between the two parallel sides.

from the given graph,

a=10 m/s

b=35 m/s

h=25 s

Hence, A= \frac{(10+35) m/s}{2}\times 25 s=562.5 m

The area under graph = 562.5 m. Hence, the total displacement is 562.5 m.


muminat3 years ago
4 0
Displacement (between time 0 and time 25) is the area under the velocity time curve, i.e. ∫ vdt.
Here, v(0)=10, v(25)=34 (approx.)
Therefore 
displacement = (1/2)(10+34 m/s)*(25-0) s   [ trapezoid area ]
=550 m
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