Ask question

Ask question

All categories

3 years ago

6

How does ionization of a given molecule affect its distribution between the organic and aqueous layer

1 answer:

iVinArrow [24]3 years ago

4 0

Answer:

Ionized molecules will be found in the aqueous layer

Explanation:

The principle of solvent extraction involves the partitioning of a substance between an aqueous layer and an organic layer. The aqueous layer is polar in nature while the organic layer is nonpolar in nature.

All nonpolar substances are found in the organic layer while all polar substances are found in the aqueous layer. Hence, in the aqueous phase, the following species can be found; positive ions, negative ions and neutral polar molecules or ionic substances.

You might be interested in

Describe how cells are organized into larger and larger groups to help living things survive

mestny [16]

Cells are organized into tissues. Tissues carry out specific functions. Groups of tissues can then form organs that also have specific functions to carry out. Lastly groups of organs form organ systems that regulate many functions in a specific part of the body.

3 0

3 years ago

A diver has 3,400 J of gravitational potential energy after climbing

Zanzabum

Answer:

57.8kg

Explanation:

Potential energy is given by:

$U =mgh$

Where U is potential energy, m is mass, g is acceleration due to gravity, and h is height. Using this equation:

$3400=m(9.8)(6)\\3400=58.8m\\m=57.8kg$

3 0

3 years ago

Is a particle with a positive charge.:)

tatyana61 [14]

Proton is the answer

8 0

3 years ago

A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4

san4es73 [151]

Answer:

83.20 g of Na3PO4

Explanation:

1 mole of Na3PO4 contains 3 moles of Na+.

Mole of Na ion to be prepared = Molarity x volume

= 0.700 x 725/1000

= 0.5075 mole

If 1 mole of Na3PO4 contains 3 moles of Na ion, then 0.5075 Na ion will be contained in:

0.5075/3 x 1 = 0.1692 mole of Na3PO4

mole of Na3PO4 = mass/molar mass = 0.1692

Hence, mass of Na3PO4 = 0.1692 x molar mass

= 0.1692 x 163.94

= 83.20 g.

83.20 g of Na3PO4 will be needed.

3 0

3 years ago

Read 2 more answers

If 12.5 grams of the original sample of cesium-137 remained after 90.6 years, what was the mass of the original sample?

myrzilka [38]

Answer:

Mass of original sample = 100 g

Explanation:

Half life of cesium-137 = 30.17 years

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac{\ln2}{t_{1/2}}$

$k=\frac{\ln2}{30.17}\ year^{-1}$

The rate constant, k = 0.02297 year⁻¹

Time = 90.6 years

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Initial concentration $[A_0]$ = ?

Final concentration $[A_t]$ = 12.5 grams

Applying in the above equation, we get that:-

$12.5\ g=[A_0]e^{-0.02297\times 90.6}$

$[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g$

<u>Mass of original sample = 100 g</u>

8 0

3 years ago