Answer:
Explanation:
Let 100 m/s  be the velocity of projection. 
So horizontal component 
= 100 cos42 
= 74.31 m /s 
Vertical component = - 100 sin 42 . in upward direction
66.91 m/s 
Net displacement = 2.1 downwards ( + ve )
Using s = ut + 1/2 gt² 
2.1 = - 66.91 t  + .5 x 9.8 x t²
4.9 t² -  66.91 t - 2.1 = 0 
t = 13.685 s 
Horizontal distance covered 
= 13.685 x 74.31 
= 1016.93 m 
If angle of projction is 40°
So horizontal component 
= 100 cos40 
= 76.60 m /s 
Vertical component = - 100 sin 42 . in upward direction
64.27 m/s 
Net displacement = 2.1 downwards ( + ve )
Using s = ut + 1/2 gt² 
2.1 = -76.60 t  + .5 x 9.8 x t²
4.9 t² -  76.60 t - 2.1 = 0 
t = 15.659  s 
Horizontal distance covered 
= 15.659 x 76.60
= 1199.49  m 
So horizontal range is increased , if angle of projection is increased .