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defon
3 years ago
8

an extended spring stores: A. radiant energy B. potential energy C. kinetic energy D. chemical energy

Physics
2 answers:
Svetradugi [14.3K]3 years ago
6 0
Potential energy

represented by PE=1/2 kx^2
where k is the spring constant and x is the displacement
Lyrx [107]3 years ago
3 0
<span>An extended spring stores is what type of Energy?

Answer:</span><span> B. Potential energy 

Good Luck! :)
</span>

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Why are certain metalloids useful in today's technological equipment?
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The answer is B.

Metalloids are elements that posses some of the characteristics of non-metals and also some of the characteristics of metals.

The semiconductivity property of metalloids such as Siliconium, Geranium have been leveraged to the maximum and these are used in LCD screens, televisions and many other technological appliances.

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3 years ago
Which wave characteristics is defined as the number of cycles of a periodic wave occurring per unit time?
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<h3><u>Answer;</u></h3>

Frequency

<h3><u>Explanation;</u></h3>
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7 0
3 years ago
Can someone solve this problem and explain to me how you got it​
evablogger [386]

Answer:

question5: F=74312.5N

question6: charge at the end of antenna=0.37N

Explanation:

Coulomb's law: the magnitude of the force of attraction or repulsion due to two charges is proportional to the product of the magnitude of the charges and inversely proportional to the square of distance between the charges.

⇒F\alpha\frac{q1*q2}{r^{2}}

∴F=k\frac{q1*q2}{r^{2}}

where F is the force of attraction or repulsion

k is Coulumb's constant=9*10^{9}Nm^{2}C^{-2}

q1 and q2 are the magnitude of the charges

r is the distance between two charges

The force between the two charges is attractive if they are of different polarity

The force between the two charges is repulsive if they are of same polarity

Question5:

Given: q1=0.041 C, q2=0.029 C, r=12 m

therefore by Coulumb's law,

F=9*10^{9}*\frac{0.041*0.029}{12^{2}}

F=74312.5N

Question6:

Given: q1=3*10^{-18}C, r=5 m, F=4*10^{-11}N

therefore by Coulumb's law,

4*10^{-11}=9*10^{9}*\frac{3*10^{-18}*q2}{5^{2}}

⇒q2=\frac{4*10^{-11}*25}{9*10^{9}*3*10^{-18}} \\=0.37C

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3 years ago
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It's about acceleration, right?

4 0
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sergiy2304 [10]

Answer:

true

Explanation:

i believe that's the answer hope that helps

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