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3 years ago

John rides his bike with a constant speed of 12 miles per hour. How far can he travel in 2 hours?

Physics

1 answer:

Gwar [14]3 years ago

5 0

Answer:

24 miles

Explanation:

Make a proportion

He is traveling at a constant rate of 12 miles/hour, so

he can go 12 miles in 1 hour, and x miles in 2 hours

12/1=x/2

Multiply both sides by 2

2*12/1=x/2 *2

24=x

So, in 2 hours he can travel 24 miles

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Water flows through a garden hose which is attached to a nozzle. The water flows through hose with a speed of 1.81 m/s and throu

Serggg [28]

Answer:

a) 17.086m

b) 0.1671 m

Explanation:

Given data: speed of water through the hose = 1.81 m/s

through the nozzle = 18.3 m/s

We know that maximum height of an object with upward velocity v is given by,

a) H = v^2/2g

where H is the maximum height water emerges

= 18.3^2/(2×9.8) = 17.086 m answer

b) Again,

H = v^2/2g

= 1.81^2/(2×9.8) = 0.1671 m

6 0

3 years ago

These three bulbs are powered by the battery. What will happen if the middle light burns out? A. The two other bulbs will go out

Anna11 [10]

Answer:

Explanation:

4 0

3 years ago

An ambulance is traveling north at 55.9 m/s, approaching a car that is also traveling north at 28.4 m/s. The ambulance driver he

wlad13 [49]

Answer:

915 Hz

Explanation:

The observed frequency from a sound source is given as

f₀ = f [(v + v₀)/(v+vₛ)]

where

f₀ = observed frequency of the sound by the observer = ?

f = actual frequency of the sound wave = 983 Hz

v = actual velocity of the sound waves = 343 m/s

vₛ = velocity of the source of the sound waves = 55.9 m/s

v₀ = velocity of the observer = 28.4 m/s

f₀ = 983 [(343+28.4)/(343+55.9)]

f₀ = 915.2 Hz = 915 Hz

6 0

3 years ago

An element has the following natural abundances and isotopic masses: 90.92% abundance with 19.99 amu, 0.26% abundance with 20.99

sashaice [31]

<u>Answer:</u> The average atomic mass of the given element is 20.169 amu.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of the isotopes each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

We are given:

For isotope 1:

Mass of isotope 1 = 19.99 amu

Percentage abundance of isotope 1 = 90.92 %

Fractional abundance of isotope 1 = 0.9092

For isotope 2:

Mass of isotope 2 = 20.99 amu

Percentage abundance of isotope 2 = 0.26%

Fractional abundance of isotope 2 = 0.0026

For isotope 3:

Mass of isotope 3 = 21.99 amu

Percentage abundance of isotope 3 = 8.82%

Fractional abundance of isotope 3 = 0.0882

Putting values in equation 1, we get:

$\text{Average atomic mass}=[(19.99\times 0.9092)+(20.99\times 0.0026)+(21.99\times 0.0882)]$

$\text{Average atomic mass}=20.169amu$

Hence, the average atomic mass of the given element is 20.169 amu.

4 0

3 years ago

What does friction mean?

WARRIOR [948]

Rubbing on something

5 0

3 years ago