All categories

3 years ago

Help me how do you do this ?? ASAP HELPPPP

Physics

1 answer:

Nataly [62]3 years ago

8 0

cant really answer here with text but at the top of the slide it should br positives and towards the bottom its negative.

This is because you go faster at the top of the slide than the bottom and when your at the bottom you slow down

You might be interested in

Part D

Montano1993 [528]

Answer:

Explanation:

I literally just did this question lol I hope I helped

4 0

2 years ago

Which physical property of iron is being tested in the picture

Molodets [167]

Answer:

Electrical Conductivity

Explanation:

it was on test

7 0

3 years ago

At sunset, the sun appears reddish. What is MOST LIKELY the reason for this phenomenon?

Alexeev081 [22]

The only correct statement on the list is choice-A./

3 0

3 years ago

Read 2 more answers

If an object suspended by a scale shows a weight of 3 N in air, and 2 N when submerged in water, the buoyant force on the submer

Alex Ar [27]

Answer:

1 N

Explanation:

Buoyant Force: This is also called upthrust, It can be defined as the force which act upward exerted by a fluid when an object is placed in it.

The S.I unit is Newton.

From the question,

Buoyant force = Weight of the object in air- weight of the object when submerged in water.

U = W-W'.......................... Equation 1

Where U = upthrust, W = weight in air, W' = weight when submerged in water.

Given: W = 3 N, W' = 2 N

Substitute into equation 1

U = 3-2

W = 1 N

7 0

2 years ago

The diagram shows waves of sound travelling through the air. By which factor is the sound intensity decreased at 3 meters?

SIZIF [17.4K]

The diagram is missing; however, we know that the intensity of a sound wave is inversely proportional to the square of the distance from the source:
$I(r)= \frac{1}{r^2}$
where I is the intensity and r is the distance from the source.

We can assume for instance that the initial distance from the source is r=1 m, so that we put
$I= \frac{1}{r^2}= \frac{1}{(1)^2}=1$
The intensity at r=3 m will be
$I= \frac{1}{r^2}= \frac{1}{(3)^2}= \frac{1}{9}$
Therefore, the sound intensity has decreased by a factor $1/9$ .

8 0

2 years ago

Read 2 more answers