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4 years ago

Help me how do you do this ?? ASAP HELPPPP

Physics

1 answer:

Nataly [62]4 years ago

8 0

cant really answer here with text but at the top of the slide it should br positives and towards the bottom its negative.

This is because you go faster at the top of the slide than the bottom and when your at the bottom you slow down

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Bart runs up a 2.91 meters high flight of stairs at a constant speed in 2.15 seconds. If barts mass is 65.9kg determine the work

Tanzania [10]

Answer:

1879.33J

874.1W

Explanation:

Given parameters:

Distance covered = 2.91m

Time taken = 2.15s

Mass of Bart = 65.9kg

Unknown:

Work done = ?

Power rating = ?

Solution:

Here, the work done is related to the the potential energy in climbing this flight of stairs.

Work done = Potential energy = mgH

where m is the mass

g is the acceleration due to gravity

H is the height

Work done = 65.9 x 9.8 x 2.91 = 1879.33J

Power is defined as the rate at which work is being done.

Power = $\frac{Work done }{time taken}$

= $\frac{1879.33}{2.15}$

= 874.1W

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3 years ago

Define electric current and drift velocity.

Blizzard [7]

Answer:

Current- the flow of free charges, such as electrons and ions

Drift velocity- the average speed at which these charges move

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3 years ago

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Which of the following is neutral?

Sauron [17]

Answer:

atoms and neutrons

Explanation:

electrons have a negative charge

protons have a positive charge

cations are positive ions

anions are negative ions

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3 years ago

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A small block of mass M = 0.10 kg is released from rest at point 1 at a height H = 1.8 m above the bottom of a track, as shown i

Ede4ka [16]

Answer:

Explanation:

A) is not correct, because the gravitation potential energy will depend on the height the block is located at. It will be calculated with the formula:

U=mgh.

If we take the ground as a zero height reference, then on point 2 the potential energy will be:

$U_{2} = 0.10kg(9.81 m/s^{2})(0.6m)$

$U_{2}=0.59 J$

While on point 3, the potential energy will be greater.

$U_{3}=0.10kg(9.81 m/s^{2})(1.2m)$

$U_{3}=1.18 J$

B) is not the right answer because the kinetic energy will vary with the height the block is located at in the fact that the energy is conserved (this is if we don't take friction into account or air resistance) so in this case:

$U_{2}+K_{2}= U_{3}+K_{3}$

We already know the potential energy at point 2. We can calculate the kinetic energy at point 3 like this:

$K_{3} =\frac{1}{2}mv_{3}^{2}$

$K_{3} =\frac{1}{2}(0.10kg)(2.5 m/s)^{2}$

$K_{3} =0.31 J$

So the kinetic energy at point 2 is given by the equation:

$K_{2} =U_{3}-U_{2}+K_{3}$

so:

$K_{2} = (1.18J)-(0.59J)+0.31J$

$K_{2} =0.9J$

As you may see the kinetic energy at point 2 is greater than the kinetic energy at point 3.

C) Is not correct because according to the first law of thermodinamics, energy is not lost, only transformed. So, since we are not taking into account friction or any other kind of loss, then we can say that the amount of mechanical energy at point 1 is exactly the same as the mechanical energy at point 3.

D) Because of what we talked about on part C, this will be the true situation, because the mechanical energy of the block will be the same no matter theh point you measure it at.

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Describe how sound signals can be transmitted from a radio station and received on a radio at your home. Create a labeled diagra

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A radio wave is generated by a transmitter and then detected by a receiver. An antenna allows a radio transmitter to send energy into space and a receiver to pick up energy from space. Transmitters and receivers are typically designed to operate over a limited range of frequencies

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