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3 years ago

A proposed answer to a scientific problem is a _.

Physics

1 answer:

liubo4ka [24]3 years ago

7 0

Answer:

A proposed answer to a s scientific problem is a hypothesis.

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A light bulb connects to a battery. A second, identical light bulb connects in parallel to the first light bulb. The connecting

mr Goodwill [35]

Answer:d

Explanation:

Suppose V is the voltage of battery and R is the resistance of bulb

so Power drop for initial stage

$P_1=\frac{V^2}{R}$

When another identical bulb of same resistance is applied in parallel so voltage Drop across both the resistor will be same i.e. V

so Power consumed $P_2=\frac{V^2}{R}$

so there is no change in power and hence no dip in brightness

8 0

3 years ago

If a car traveled 60 m in 30 s, what is the velocity?*

klemol [59]

Answer:

6.56168

Explanation:

8 0

3 years ago

A particle is projected at an angle 60 degrees to the horizontal with a speed of 20m/s. (i) calculate total time of flight of th

Kisachek [45]

Answer:

Time of flight=3.5 seconds

Speed at maximum height is 0

Explanation:

Φ=60°

initial velocity=u=20m/s

Acceleration due to gravity=g=9.8 m/s^2

Total time of flight=T

Final speed=v

question 1:

T=(2 x u x sinΦ)/g

T=(2 x 20 x sin60)/9.8

T=(2 x 20 x 0.8660)/9.8

T=34.64/9.8

T=3.5 seconds

Question 2

Speed at maximum height is 0

8 0

3 years ago

Determine how many gallons of jet fuel the jet can hold and still be able to takeoff from sea level with an outside temperature

zysi [14]

Question:

For a certain commercial jet to be able to achieve liftoff, its total weight cannot exceed 333,390 kg. If the empty weight (i.e., no fuel or passengers) of the jet is 163,293 kg and there are 300 passengers aboard with an average weight of 75.0 kg, determine how many gallons of jet fuel the jet can hold and still be able to takeoff from sea level with an outside temperature of 277 K. The specific gravity of jet fuel is 0.804

Answer:

The answer to the question is;

The jet can hold 48642.2 gal or 40503 galUK of jet fuel and still be able to takeoff from sea level.

Explanation:

To solve the question, we note the following

Maximum total weight at liftoff = 333,390 kg

Mass of jet when empty = 163,293 kg

Average mass of one passenger = 75.0 kg

Number of persengers = 300

Total mass of persengers = 300×75 =22500 kg

Mass of jet + passengers = 163293 + 22500 = 185793 kg

Allowable mass jet carry = Mass of jet fuel

= Maximum total weight at liftoff - Mass of jet + passengers

= 333,390 kg - 185,793 kg = 147597 kg

Specific gravity of jet fuel = 0.804 therefore density of jet fuel is given by

Density of jet fuel = Density of water × The specific gravity of jet fuel

= 997 kg/m³ × 0.804 = 801.588 kg/m³

Volume of jet fuel = (Mass /Density) of the jet fuel = $\frac{147597 }{801.588}$ = 184.131 m³

However 1 m³ = 264.172 gal = 219.969 galUK

∴ 184.131 m³ = 264.172× 184.131 gal

= 48642.2 gal = 40503 galUK

4 0

3 years ago

| 'The force needed to push a load up an inclined

dexar [7]

Explanation:

Since less effort is needed in lifting a load to a higher level by moving over an inclined plane as compared to that in lifting the load directly, an inclined plane acts as a force multiplier. This is because the mechanical advantage of an inclined plane is always greater than 1.

3 0

3 years ago