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katrin2010 [14]
2 years ago
13

A proposed answer to a scientific problem is a _.

Physics
1 answer:
liubo4ka [24]2 years ago
7 0

Answer:

A proposed answer to a s scientific problem is a hypothesis.

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What is the Ultraviolet Catastrophe?​
Sholpan [36]

The ultraviolet catastrophe was the prediction of late 19th century/early 20th century classical physics that an ideal black body (also blackbody) at thermal equilibrium will emit radiation in all frequency ranges, emitting more energy as the frequency increases.

7 0
3 years ago
A man has a mass of 110kg. What is his weight?
Stells [14]

His weight depends on where he is, because

Weight = (mass) x (gravity in the place where the mass is) .

For example:

-- If this man is on Mars, his weight is (110 kg) x (3.7 m/s²) =  408 Newtons

-- If he is on the Moon, his weight is (110 kg) x (1.6 m/s²) =  176 Newtons

-- If he is on Earth, his weight is (110 kg) x (9.8 m/s²) =  1,078 Newtons

-- If he is in a spacecraft coasting from one to another, his weight is zero.

5 0
2 years ago
The formula K2S indicates that
jekas [21]
There are two atoms of potassium bonded to one atom of sulfur.
4 0
3 years ago
Acceleration is generally defined as the time rate of change of velocity. When can it be defined as the time rate of change of s
Lena [83]

Answer:

When the velocity doesn't change its direction

Explanation:

Since velocity vector has 2 components: direction and magnitude, and speed is the velocity's magnitude. So if the velocity doesn't change its direction, we essentially use its magnitude, aka speed, to calculate the rate of change for acceleration.

8 0
3 years ago
Read 2 more answers
It's nighttime, and you ve dropped your goggles into a 3.2-m-deep swimming pool. If you hold a laser pointer 0.90 m above the ed
yanalaym [24]

Answer:

The distance of the goggle from the edge is 5.30 m

Explanation:

Given:

The depth of pool (d) = 3.2 m

let 'i' be the angle of incidence

thus,

i = tan^{-1}(\frac{2.2}{0.90})

i = 67.75°

Now, Using snell's law, we have,

n₁ × sin(i) = n₂ × 2 × sin(r)

where,

r is the angle of refraction

n₁ is the refractive index of medium 1 = 1 for air

n₂ is the refractive index of medium 1 = 1.33 for water

now,

1 × sin 67.75° = 1.33 × sin(r)

or

r = 44.09°

Now,  

the distance of googles = 2.2 + d×tan(r)  = 2.2 + (3.2 × tan(44.09°) = 5.30 m

Hence, <u>the distance of the goggle from the edge is 5.30 m</u>

5 0
3 years ago
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