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harina [27]
3 years ago
5

A lunar vehicle is tested on earth at a speed of 12 km/h. When it travels at the same speed on the moon, is its momentum greater

, less, or the same
Physics
1 answer:
Leona [35]3 years ago
3 0

Momentum is defined as product of mass and velocity

so it is

P = mv

so here since velocity will remain same as that is on the surface of earth

As well as the mass is always conserved

so here neither mass nor the velocity will change when it is moving on moon

<em>So the momentum will remain unchanged and remain the same</em>

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the mass of an object is 90 kg calculate weight of the same object on the surface of the moon.(acceleration due to gravity on th
aalyn [17]

Explanation:

the weight of an object is its force exerted by gravity.

on earth we take gravitational acceleration to be 9.8 m/s^2

so the weight of an object on earth is given by F = mg

hence,

F = 90 × 9.8

F = 882 Newtons (weight on earth)

gravitational acceleration on the moon is equal to 9.8/6. so, we can just use the same formula to find the weight on the moon.

F = 90 × 9.8/6

F = 147 Newtons (weight on the moon)

make sure to ask if you need any further guidance.

5 0
2 years ago
Read 2 more answers
Same object differs in water than in air?
Ipatiy [6.2K]

Answer:

Yes

Say that I have a bomb that is triggerded when it is in water. In air the bomb does not change, but in water it blows up.

8 0
3 years ago
Peter notices that his eight-year-old daughter frequently mentions the unusual habits of a new boy, who is from a different cult
pickupchik [31]
The answer should be C. Encourage his daughter to make friends with the new boy.

Hope this helps and have a happy new year
6 0
3 years ago
An electron, starting from rest and moving with a constant acceleration, travels 2.0 cm in 5.0 ms. What is the magnitude of this
IrinaK [193]
 <span>s=2.7 centimeters = 0.027 meters 
t=3.9 milliseconds = 0.0039 seconds 

s=(1/2)a*t^2 
so 
a=(2.7*2)/(0.0039)^2 
= 355,029.58 m/s^2 

a=355,029.58 m/s^2 = 355.02958 km / s^2</span>
7 0
3 years ago
A force of 350N is applied to a body. If the work done is 40kJ, what is the distance through which the body moved?
Studentka2010 [4]

The distance covered by the body is 114.3 m

Explanation:

The work done by a force exerted on an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

For the object in this problem, we have

F = 350 N is the force applied

W=40 kJ = 40,000 J is the work done

\theta=0^{\circ} if we assume that the force is applied parallel to the motion of the object

Solving for d, we find the distance covered by the object:

d=\frac{W}{F cos \theta}=\frac{40,000}{(350)(cos 0)}=114.3 m

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

7 0
3 years ago
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